I went with defaultdict to accumulate sums and counts in one pass, then divided at the end and sorted with sorted() using a lambda on the value.
First, clarify the requirements: what to do with missing values, whether to sort the dictionary itself or return a sorted list of tuples, and the expected output format. Then, implement an efficient solution using a dictionary to accumulate sums and counts per user, compute averages, and sort by descending average. Finally, discuss time and space complexity and potential edge cases.
Pro tip: Mention that Python dictionaries preserve insertion order (since 3.7), so if you need a sorted dictionary, you can build it from sorted items; otherwise, returning a list of (user_id, average) tuples sorted by average is often more practical. Also, consider using collections.defaultdict for cleaner accumulation.
Ask about handling missing values, non-numeric values, empty input, and whether the output should be a dictionary or a sorted list. Confirm if sorting is by average value descending and if ties need a secondary sort.
Use a dictionary to map user_id to a list of values, or two dictionaries for sum and count. Consider collections.defaultdict for efficient accumulation.
Iterate through events, accumulate sum and count per user, then compute average for each user. Handle division by zero if a user has no events (though unlikely).
Sort the user averages using sorted() with key=lambda x: x[1], reverse=True. If returning a dictionary, build it from the sorted items.
State time complexity O(n + m log m) where n is number of events and m is number of users, and space O(m). Walk through a small example to verify correctness.
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