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Meta·Software Engineer·Onsite - Coding / Algorithms·Intermediate

IntermediatePrefer not to say
May 2026

Summary

Meta SWE coding round with two array problems back to back. Nothing too wild but the second one definitely took more time to think through than I expected.

Questions Asked (2)

Q1

Given an integer array, return a new array where each element is the product of all other elements in the original array. No division allowed, and it must run in O(n) time.

Algorithms & Data Structures
Author's notes

The no-division constraint is the whole point of the problem.

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AI HintsAI Generated

Suggested Approach

Use prefix and suffix products to compute the result in two passes without division. First, compute prefix products from left to right, then multiply by suffix products from right to left. This achieves O(n) time and O(n) space (or O(1) extra space if output array is reused).

Pro tip: Clarify edge cases upfront: what if the array contains zeros? The prefix-suffix approach handles zeros naturally, but be prepared to discuss how many zeros and their positions affect the result. Also, mention that you can optimize space by using the output array to store prefix products first, then update it with suffix products in a second pass.

1. Understand the problem and constraints

Restate the problem: given an array, return an array where each element is the product of all other elements. Note the constraints: no division, O(n) time. Ask clarifying questions about input size, possible zeros, and whether the output array counts towards space complexity.

2. Brainstorm approaches

Consider brute force O(n^2) and explain why it's suboptimal. Think about how to avoid division: use prefix and suffix products. Discuss the idea of computing products of all elements to the left and right of each index.

3. Design the algorithm

Describe the two-pass approach: first pass compute prefix products and store in output array; second pass compute suffix products on the fly and multiply with the prefix products in the output array. This yields the desired result in O(n) time and O(1) extra space (excluding output).

4. Analyze complexity and edge cases

State time complexity O(n) and space complexity O(n) for output (or O(1) extra). Discuss edge cases: empty array, single element, multiple zeros, negative numbers. Explain how the algorithm handles them.

5. Implement and test

Write clean code with meaningful variable names. Walk through a small example to verify correctness. If time permits, discuss potential optimizations or alternative approaches (e.g., using logarithms, but note precision issues).

Key Points to Mention

  • Prefix and suffix product arrays
  • Two-pass algorithm with O(n) time
  • Space optimization by reusing output array
  • Handling zeros and edge cases
  • No division constraint
  • Time and space complexity analysis

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Given a 2D binary matrix representing Conway's Game of Life, compute the next generation state of the board based on the standard neighbor survival and birth rules.

Algorithms & Data Structures
Author's notes

This one tripped me up more than I'd like to admit.

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AI HintsAI Generated

Suggested Approach

Clarify the rules and constraints, then propose an in-place solution using bit manipulation to encode the next state without extra space. Walk through the algorithm, handle edge cases, and analyze time and space complexity.

Pro tip: Mention that using two bits per cell (e.g., LSB for current state, next bit for next state) allows in-place updates and avoids extra memory, which is often expected at Meta. Also, discuss how to handle infinite boards if asked.

1. Clarify rules and constraints

Confirm the exact survival and birth rules, and ask about board size, whether it's finite or infinite, and if in-place modification is allowed.

2. Choose representation

Decide on a representation that allows efficient updates, such as using two bits per cell to store both current and next state, or using a separate board if extra space is acceptable.

3. Compute next state

Iterate through each cell, count live neighbors using the current state, apply the rules, and store the next state in the extra bit or separate board.

4. Update board

After processing all cells, shift the next state into the current state (e.g., right shift by 1) to finalize the next generation.

5. Analyze complexity and edge cases

State time complexity O(m*n) and space complexity O(1) if using bit manipulation, and discuss edge cases like empty board, single row/column, and all live/dead cells.

Key Points to Mention

  • Neighbor counting: check all 8 directions, handle boundaries carefully.
  • In-place update using bit manipulation: store next state in the second bit to avoid extra space.
  • Time complexity: O(m*n) where m and n are dimensions.
  • Space complexity: O(1) if in-place, otherwise O(m*n) for a separate board.
  • Edge cases: empty board, 1x1 board, boards with all live or all dead cells.
  • Potential follow-up: how to handle infinite board (e.g., using a hash set of live cells).

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.