Knew this one but still fumbled the explanation a bit at first.
Use a min-heap to efficiently merge the N sorted lists by repeatedly extracting the smallest element and inserting the next element from the same list. This yields O(M log N) time where M is total elements, and O(N) space for the heap. Alternatively, mention divide-and-conquer merging for O(M log N) time and O(1) extra space if merging in-place, but highlight the heap approach as optimal for streaming or large N.
Pro tip: Discuss trade-offs: the heap approach is better for online/streaming scenarios and when N is large, while divide-and-conquer may be preferred if memory is constrained or if lists are on disk. Also, clarify assumptions about list sizes and whether input can be modified.
Confirm the number of lists (N), total elements (M), and whether lists are sorted ascending. Ask about constraints like memory limits, input size, and if the output should be a new list or can be in-place.
Mention the straightforward approach of concatenating all lists and sorting, which takes O(M log M) time, to establish a baseline and show you can think simply before optimizing.
Explain using a min-heap of size N, where each heap element stores the value and its list index. Repeatedly extract the minimum, append to output, and insert the next element from the same list if available.
Time: O(M log N) because each of M elements is inserted and extracted from the heap in O(log N). Space: O(N) for the heap plus O(M) for the output (or O(1) extra if output is not counted).
Mention divide-and-conquer merging (pairwise merge) which also gives O(M log N) time but O(1) extra space if merging in-place, and compare with the heap approach in terms of memory, streaming capability, and implementation complexity.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.