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The base function was fine, just loop the diagonal.
Start by explaining the straightforward O(n) trace computation, then introduce the O(1) update design by maintaining running sums for the main and anti-diagonals. For each update, adjust the sums based on whether the changed cell lies on either diagonal, and discuss edge cases and complexity.
Pro tip: Emphasize that the O(1) update is achieved by precomputing the initial sums and then applying constant-time adjustments per update, and proactively mention how to handle non-square matrices by defining diagonals only for square submatrices or returning an error.
Confirm the definition of main diagonal (i == j) and anti-diagonal (i + j == n - 1), and ask whether the matrix is guaranteed square. Discuss how to handle non-square inputs (e.g., return error or use min(rows, cols)).
Maintain the matrix itself, plus two running sums: main_sum and anti_sum. Initialize them by iterating over the diagonals in O(n) time. For updates, adjust the sums in O(1) by subtracting the old value and adding the new value if the cell belongs to the respective diagonal.
For update(i, j, val): if i == j, main_sum += val - matrix[i][j]; if i + j == n - 1, anti_sum += val - matrix[i][j]; then set matrix[i][j] = val. For trace(), return main_sum; for anti_trace(), return anti_sum.
Initialization O(n), each update O(1), each query O(1). Space O(n^2) for the matrix. Edge cases: n=0 or 1, non-square input, very large n (memory concerns), and updates to cells not on diagonals (no change to sums).
Mention that if updates are frequent and queries rare, recomputing on demand might be simpler; if memory is tight, consider storing only diagonal elements and a sparse representation for off-diagonal updates. Also note that for non-square matrices, the concept of main diagonal is ambiguous.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.