I started with the naive transpose-into-a-new-matrix approach just to get something on the board, and they let me finish before asking about the space.
Explain the two-step in-place rotation: first transpose the matrix by swapping elements across the main diagonal, then reverse each row to achieve a 90-degree clockwise rotation. Emphasize that this uses O(1) extra space and O(n^2) time, which is optimal since every element must be moved.
Pro tip: Mention that the same technique can be adapted for counter-clockwise rotation (transpose then reverse columns) and that in-place operations are crucial for memory-constrained ML deployments on edge devices.
Restate the problem to ensure understanding: rotate an n x n matrix 90 degrees clockwise in place, without allocating a second matrix. Confirm that the matrix is square and that in-place means O(1) extra space.
Explain that the rotation can be decomposed into two operations: (1) transpose the matrix (swap matrix[i][j] with matrix[j][i] for i < j), and (2) reverse each row. This yields the 90-degree clockwise rotation.
Use a small matrix (e.g., 3x3) to illustrate the steps. Show the matrix before and after transpose, and then after row reversal, to demonstrate the transformation.
State that the algorithm performs O(n^2) operations (each element is visited a constant number of times) and uses O(1) extra space, which is optimal for this problem.
Mention handling of 1x1 matrices, empty matrices (if allowed), and ensure that the in-place swaps are done correctly without overwriting values. Also note that the order of operations (transpose then reverse rows) is crucial for clockwise rotation.
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