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Amazon·Software Engineer·Technical Phone Screen·Intermediate

IntermediatePrefer not to say
Jun 2026Remote

Summary

Amazon SWE coding round, pretty standard graph traversal territory. The question had a few layers to it so it wasn't just 'write BFS and leave', they wanted to see you think through complexity and edge cases too.

Questions Asked (1)

Q1

Given a 2D grid of 0s and 1s, count the number of connected regions made up of 1s. Cells connect in four directions. Walk through both a recursive and an iterative solution, explain how you prevent revisiting cells, and discuss time and space complexity. Handle edge cases like empty grids or very large inputs.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

I started with the recursive DFS and it went fine, but when they asked me to do the stack-based version I fumbled a bit on the order I was pushing neighbors.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the problem and edge cases, then explain the core idea of traversing each unvisited '1' and exploring its connected component using DFS (recursive or iterative) or BFS. Compare recursive and iterative implementations, emphasizing how to mark visited cells to avoid cycles, and analyze time and space complexity. Finally, discuss handling large inputs and potential optimizations.

Pro tip: Mention that for very large grids, recursion may cause stack overflow, so an iterative approach with an explicit stack or BFS is safer; also note that modifying the grid in-place to mark visited cells saves space but may not be allowed if input must be preserved.

1. Clarify the problem and edge cases

Confirm the definition of connected regions (4-directional), and discuss edge cases such as empty grid, grid with no 1s, or grid with all 1s. Also ask about input size constraints to choose the right approach.

2. Explain the high-level approach

Iterate through each cell; when a '1' is found and not visited, increment the region count and traverse all connected '1's using DFS or BFS, marking them as visited.

3. Walk through recursive DFS

Describe a recursive function that marks the current cell as visited and recursively calls itself on all four adjacent cells that are '1' and not visited. Mention base cases and how to avoid revisiting.

4. Walk through iterative solution

Use an explicit stack (DFS) or queue (BFS) to explore the region. Push the starting cell, then while the stack/queue is not empty, pop a cell, mark it visited, and push all unvisited adjacent '1's.

5. Analyze complexity and discuss trade-offs

Time complexity is O(m*n) since each cell is visited once. Space complexity is O(m*n) in the worst case for the recursion stack or queue. Discuss how to handle very large inputs, e.g., using iterative BFS to avoid stack overflow, or processing in chunks.

Key Points to Mention

  • Use a visited set or modify the grid in-place to mark visited cells, preventing infinite loops.
  • Recursive DFS is concise but risks stack overflow for large grids; iterative BFS/DFS is safer.
  • Time complexity: O(m*n) where m and n are grid dimensions, as each cell is processed at most once.
  • Space complexity: O(m*n) worst-case for recursion stack or queue, but can be O(min(m,n)) for BFS if using a queue and marking visited when enqueuing.
  • Edge cases: empty grid, no '1's, all '1's, and very large grids requiring memory-efficient traversal.
  • Potential optimizations: union-find for dynamic connectivity, or parallel processing for extremely large grids.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.