I jumped straight to checking edge count and connectivity, which was fine, but I forgot that not every node is a valid root.
First, validate that the graph is a valid binary tree by checking that it has exactly n-1 edges, is connected, and every node has at most 2 children. Then, identify the root as the node with no parent (in-degree 0) and verify that all other nodes have exactly one parent.
Pro tip: Clarify whether the graph is guaranteed to be acyclic and undirected; if not, you must also detect cycles. Mention that a binary tree can have at most one root, and if multiple nodes have in-degree 0, it's invalid.
Verify that the number of edges is exactly n-1. If not, it cannot be a tree.
Perform a BFS/DFS from any node to ensure all nodes are reachable and no cycles exist (though acyclic is given, still verify connectivity).
Calculate the in-degree (number of parents) for each node. In a valid binary tree, exactly one node has in-degree 0 (the root) and all others have in-degree 1.
Ensure every node has at most 2 children (out-degree ≤ 2). If any node has more than 2 children, it's not a binary tree.
If all checks pass, return the node with in-degree 0 as the root. Otherwise, indicate invalid.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.