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Pilot·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Apr 2026

Summary

Interviewed for a software engineer role at Pilot and got a string manipulation problem that had a sneaky constraint attached to it. Nothing too crazy but the no-sort rule tripped me up a bit.

Questions Asked (1)

Q1

Given two strings, determine whether one is an anagram of the other. You cannot use any sorting functions, and your solution must run in O(n) time with O(1) extra space.

Algorithms & Data Structures
Author's notes

The base problem is easy enough, I've done anagram checks before.

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AI HintsAI Generated

Suggested Approach

First, clarify the constraints: the strings are likely ASCII or lowercase English letters, and O(1) extra space means a fixed-size array (e.g., 256 or 26 integers) is acceptable. Then, propose a frequency count approach: iterate through both strings, incrementing counts for the first and decrementing for the second, and finally check that all counts are zero. Emphasize that this runs in O(n) time and uses O(1) space because the array size is constant.

Pro tip: Mention that you would confirm the character set with the interviewer, as the fixed array size depends on it (e.g., 26 for lowercase letters, 256 for ASCII). This shows attention to detail and avoids incorrect assumptions.

1. Clarify constraints and assumptions

Ask about the character set (e.g., ASCII, Unicode) and whether the strings can contain spaces or punctuation. Confirm that O(1) extra space allows a fixed-size array.

2. Check length equality

If the strings have different lengths, they cannot be anagrams, so return false immediately. This is a quick O(1) check.

3. Initialize frequency array

Create an integer array of size equal to the number of possible characters (e.g., 256 for ASCII). Initialize all counts to zero.

4. Count frequencies

Iterate through the first string, incrementing the count for each character. Then iterate through the second string, decrementing the count for each character.

5. Verify all counts are zero

After processing both strings, check that every element in the frequency array is zero. If any is non-zero, return false; otherwise, return true.

Key Points to Mention

  • Time complexity: O(n) where n is the length of the strings, as we make two passes.
  • Space complexity: O(1) because the frequency array size is constant (e.g., 256).
  • Handling of different character sets: adjust array size based on assumptions (e.g., 26 for lowercase letters).
  • Edge cases: empty strings, strings of different lengths, and strings with repeated characters.
  • Alternative approaches: XOR or sum of characters (but note these can fail due to collisions or overflow).
  • Early termination: if lengths differ, return false immediately.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.