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My first instinct was brute force O(n^2) and I said so out loud, which I think was fine.
Clarify the problem constraints (n, coordinate ranges, whether segments are inclusive) and discuss a sweep-line algorithm with a Fenwick tree to count intersections efficiently. Explain how to handle active segments and compute counts for each segment, then analyze time and space complexity.
Pro tip: Mention that sorting events by coordinate and processing starts before ends ensures touching endpoints are counted as intersections, avoiding off-by-one errors. Also, note that the problem can be solved in O(n log n) time, which is optimal for comparison-based sorting.
Ask about input size, coordinate ranges, whether segments can overlap completely, and if touching endpoints count. Confirm output format and edge cases.
Propose a sweep-line approach: sort all endpoints, use a Fenwick tree (BIT) to maintain active segments, and count intersections for each segment.
Process events in order: for a start event, query the BIT for active segments that intersect; for an end event, update the BIT. Handle ties by processing starts before ends.
For each segment, count intersections with active segments, ensuring each pair is counted once. Adjust for self-counting and duplicate segments if necessary.
State O(n log n) time and O(n) space. Walk through a small example to verify correctness, including edge cases like nested or touching segments.
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