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The bulls part is easy, just a single pass comparison.
Use a two-pass counting approach: first count bulls by comparing digits at the same index, then count cows by tracking the frequency of remaining digits in the secret and matching them with remaining guess digits. This avoids double-counting and runs in O(n) time with O(1) space (since digits are 0-9).
Pro tip: Clarify edge cases upfront, such as repeated digits and input length assumptions, and mention that the solution is O(n) time and O(1) space due to the fixed digit set. This shows attention to detail and efficiency.
Ask about input format (strings or integers), length equality, and handling of repeated digits. Confirm that bulls take precedence over cows.
Iterate through both strings simultaneously and increment bulls when digits match at the same position. Mark these positions as used to avoid counting them as cows.
For non-bull positions, count the frequency of each digit in the secret and in the guess. The number of cows is the sum of the minimum frequencies for each digit.
Construct the string in the format 'xAyB' using the counts of bulls and cows.
State that the algorithm runs in O(n) time and O(1) space (since digits are 0-9). Walk through a few test cases, including repeated digits.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.