Classic problem but I still fumbled the edge case where one interval completely swallows the next.
Start by clarifying the problem constraints (e.g., whether intervals are sorted, inclusive/exclusive boundaries, and expected output format). Then propose an efficient algorithm: sort intervals by start time and merge overlapping ones in a single pass. Walk through an example to demonstrate correctness and analyze time/space complexity.
Pro tip: Mention edge cases upfront (empty input, single interval, all overlapping, no overlaps) and discuss how your solution handles them. This shows thoroughness and often impresses interviewers at top companies like Google.
Ask about input size, whether intervals are sorted, boundary conditions (inclusive/exclusive), and expected output format. Confirm if intervals are given as pairs [start, end].
Explain that sorting by start time allows merging in a single pass. Mention that this reduces the problem to comparing each interval with the last merged one.
Describe: sort intervals by start; initialize result with first interval; for each subsequent interval, if it overlaps with the last in result, merge by updating the end to max of both ends; else append it.
State time complexity O(n log n) due to sorting, space O(n) for output (or O(log n) if in-place). Discuss edge cases: empty list, single interval, intervals with same start, touching intervals (end == start).
Walk through a simple example (e.g., [[1,3],[2,6],[8,10],[15,18]]) to show merging. Also test edge cases like [[1,4],[4,5]] to clarify if touching intervals merge (depends on definition).
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