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Stripe·Software Engineer·Technical Phone Screen·Intermediate

IntermediatePrefer not to say
May 2026Remote

Summary

Stripe coding screen for a software engineer role. One problem, data-heavy, and more nuanced than it looks on the surface.

Questions Asked (1)

Q1

Given two CSV-like datasets (customer rows and processor rows), each sorted and with a header row, implement a LEFT JOIN on a specified column name that appears in both headers. Every customer row must appear in the output; unmatched rows get empty strings for the processor columns.

Algorithms & Data StructuresData ModelingTechnical Trade-offs
Author's notes

I jumped straight to a hash map approach and the interviewer nudged me toward using the sorted property.

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AI HintsAI Generated

Suggested Approach

Clarify the exact join semantics and output format, then propose a two-pointer merge join that exploits the sorted order of both datasets. Walk through the algorithm step by step, handling duplicate keys and unmatched rows, and analyze time and space complexity.

Pro tip: Explicitly discuss how you would handle duplicate join keys in the processor dataset, since a naive two-pointer approach can miss matches if not advanced correctly. Mention that you'd validate the join column exists in both headers and decide on a consistent output schema before coding.

1. Clarify requirements and edge cases

Confirm the join column name, output column order, handling of duplicate keys, and whether headers should be included in the output. Ask about memory constraints to decide between streaming and in-memory approaches.

2. Choose the algorithm

Since both datasets are sorted, use a two-pointer merge join for O(n+m) time and O(1) extra space (excluding output). If sorted order weren't guaranteed, consider hash join or sorting first.

3. Outline the two-pointer logic

Iterate through customer rows; for each, advance the processor pointer while processor key < customer key. If keys match, emit joined row(s); otherwise emit customer row with empty processor fields.

4. Handle duplicates and output

For duplicate processor keys, emit one output row per matching processor row. Ensure every customer row appears at least once, with empty strings for unmatched processor columns.

5. Analyze complexity and trade-offs

State time complexity O(n+m) and space O(1) auxiliary. Discuss trade-offs: two-pointer requires sorted input; hash join is O(n+m) time but O(m) space and doesn't require sorting.

Key Points to Mention

  • Leveraging sorted order for an efficient two-pointer merge join
  • Handling duplicate join keys correctly (cartesian product per key)
  • Ensuring every customer row appears in output (LEFT JOIN semantics)
  • Using empty strings for unmatched processor columns
  • Time and space complexity analysis (O(n+m) time, O(1) auxiliary space)
  • Edge cases: empty datasets, missing join column, header-only files

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.