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Current·Software Engineer·Onsite - Coding / Algorithms·Intermediate

IntermediatePrefer not to say
Jul 2026

Summary

Coding round at Current for a software engineer role, three back-to-back algorithm problems with a clear emphasis on complexity analysis alongside the actual code. Nothing too wild but the segment tree discussion at the end caught me a bit flat-footed.

Questions Asked (3)

Q1

Given a list of transactions where each entry has a userId and an amount (positive for credits, negative for debits), compute the final balance per userId and return a map. You also need to discuss time and space complexity for large inputs.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Pretty standard aggregation problem.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the input format and expected output, then propose a single-pass hash map solution that accumulates balances per userId. After presenting the code, analyze time and space complexity, and discuss trade-offs for large inputs such as memory usage and potential distributed approaches.

Pro tip: Mention that you would use a hash map for O(1) average-case updates, but also discuss how you would handle hash collisions or worst-case scenarios, and consider streaming or partitioning if the data doesn't fit in memory.

1. Clarify requirements and assumptions

Ask about input size, data types, whether userIds are strings or integers, and if the output should include users with zero balance. Confirm that amounts can be large and that we need to handle potential overflow.

2. Design the algorithm

Propose iterating through the list once, using a hash map to accumulate amounts per userId. For each transaction, update the map: balance[userId] += amount. Initialize missing keys to 0.

3. Analyze complexity

State that time complexity is O(n) for n transactions, assuming O(1) average hash map operations. Space complexity is O(u) where u is the number of unique users, which is at most n.

4. Discuss scalability and trade-offs

For very large inputs that don't fit in memory, discuss external sorting, partitioning by userId, or using a distributed framework like MapReduce. Mention that hash map may have worst-case O(n) operations if collisions are severe, but this is rare with good hash functions.

5. Consider edge cases and optimizations

Handle empty input, users with net zero balance, and potential integer overflow by using appropriate data types (e.g., long). Optionally, mention that if userIds are known and limited, an array could be more efficient.

Key Points to Mention

  • Use a hash map (dictionary) to accumulate balances per userId.
  • Time complexity: O(n) average case, O(n) worst case if hash collisions cause O(n) operations per lookup.
  • Space complexity: O(u) where u is number of unique users, up to O(n).
  • For large inputs, consider streaming or partitioning if data doesn't fit in memory.
  • Handle edge cases: empty list, zero net balance, integer overflow.
  • Trade-offs: hash map vs. sorting (O(n log n) time, O(1) extra space if sorted in-place) vs. array if userIds are dense.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Given an array of positive integers and a list of target values, for each target find the shortest prefix length k such that the sum of the first k elements is at least the target. Return -1 if no such k exists. Implement this using a prefix-sum array combined with binary search and analyze the complexity.

Algorithms & Data Structures
Author's notes

The prefix-sum construction was fine, but I fumbled the binary search boundary conditions on the first pass.

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AI HintsAI Generated

Suggested Approach

First, build a prefix-sum array where each element is the cumulative sum up to that index. Since the array contains positive integers, the prefix sums are strictly increasing, so for each target you can binary search for the first index where the prefix sum is at least the target. If no such index exists, return -1.

Pro tip: Mention that the positivity of the integers is crucial for monotonicity, enabling binary search; if zeros or negatives were allowed, the approach would need modification. Also, clarify that the prefix sum array should be 1-indexed or include a leading 0 to simplify the binary search for the first k elements.

1. Clarify assumptions and edge cases

Confirm that the array contains only positive integers and that targets can be any positive integer. Discuss edge cases: empty array, target larger than total sum, target equal to 0, and multiple targets.

2. Build prefix sum array

Create an array prefix where prefix[i] is the sum of the first i elements (with prefix[0] = 0). This takes O(n) time and O(n) space.

3. Binary search for each target

For each target, use binary search on the prefix array to find the smallest index k such that prefix[k] >= target. If no such k exists (i.e., target > prefix[n]), return -1.

4. Analyze complexity

Time complexity: O(n + m log n) where n is the array length and m is the number of targets. Space complexity: O(n) for the prefix array. Mention that if m is large, preprocessing the prefix array is efficient.

5. Discuss potential optimizations

If targets are sorted, you could use a two-pointer approach to achieve O(n + m) time, but binary search is simpler and still efficient. Also, note that the prefix array can be reused for multiple queries.

Key Points to Mention

  • Prefix sum array construction and its 1-indexed or 0-indexed representation
  • Monotonicity of prefix sums due to positive integers, enabling binary search
  • Binary search implementation details: finding lower bound (first index where prefix sum >= target)
  • Handling of edge cases: target larger than total sum, empty array, target 0
  • Time and space complexity analysis: O(n + m log n) time, O(n) space
  • Alternative approaches (e.g., two-pointer if targets sorted) and trade-offs

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q3

For an immutable array with only a few range-sum queries and no updates, write a recursive divide-and-conquer function to answer a single query. Then explain when you would build a segment tree instead and compare the trade-offs between the two approaches.

Algorithms & Data StructuresTechnical Trade-offsSystem Design
Author's notes

I wrote the recursive function without too much trouble, but the trade-off discussion is where things got a little murky.

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AI HintsAI Generated

Suggested Approach

Start by clearly defining the recursive divide-and-conquer function for a single range-sum query, explaining the base case and how to combine results from subproblems. Then discuss the conditions under which a segment tree would be more appropriate, comparing time and space complexities, and trade-offs between the two approaches. Conclude with a recommendation based on the problem constraints.

Pro tip: Emphasize that for a few queries, the recursive approach is simpler and avoids the overhead of building a segment tree, but if queries become frequent or updates are introduced, a segment tree is more efficient. Mention that the recursive approach can be optimized with memoization or prefix sums if needed.

1. Clarify the problem and constraints

Restate the problem: immutable array, few range-sum queries, no updates. Confirm that the goal is to answer a single query efficiently, and note that the number of queries is small.

2. Design the recursive divide-and-conquer function

Define a function that takes the array, left and right bounds of the current segment, and the query range. If the segment is completely inside the query, return its sum; if disjoint, return 0; otherwise, split and recurse.

3. Analyze time and space complexity

Explain that the recursive approach has O(n) time per query in the worst case (e.g., query covers whole array) and O(log n) space due to recursion stack. For a few queries, this is acceptable.

4. Explain when to build a segment tree

Discuss that a segment tree is preferable when there are many queries (e.g., O(n) or more) or when updates are needed. Building a segment tree takes O(n) time and O(n) space, and each query/update is O(log n).

5. Compare trade-offs and conclude

Compare the two: recursive approach is simpler, uses less memory, and is sufficient for few queries; segment tree has higher upfront cost but scales better for many queries or updates. Recommend based on expected query frequency and update requirements.

Key Points to Mention

  • Base cases: segment fully inside query returns sum; disjoint returns 0.
  • Recursive splitting: divide array into halves and combine results.
  • Time complexity: O(n) per query for recursive approach, O(log n) for segment tree query.
  • Space complexity: O(log n) recursion stack vs O(n) for segment tree.
  • Segment tree build time: O(n), query/update O(log n).
  • Trade-offs: simplicity vs scalability, memory usage, and update support.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.