Use a window function (ROW_NUMBER) partitioned by user_id and ad_id, ordered by timestamp descending, to rank impressions. Then filter to the top two ranks per group and pivot using conditional aggregation (MAX(CASE WHEN rn=1 THEN timestamp END) etc.) to get the most recent and second most recent timestamps, and compute the difference in seconds. Ensure the query returns only groups with at least two impressions by filtering after ranking.
Pro tip: Explicitly mention that ROW_NUMBER is used instead of RANK or DENSE_RANK to guarantee unique sequential numbers even with ties, as specified. Also, note that the difference should be computed as the earlier timestamp minus the later timestamp (or vice versa) to get a positive value, and use TIMESTAMPDIFF or EXTRACT(EPOCH FROM ...) depending on the SQL dialect.
Use ROW_NUMBER() OVER (PARTITION BY user_id, ad_id ORDER BY timestamp DESC) to assign a rank to each impression, with the most recent getting rank 1.
In a subquery or CTE, select only rows where the rank is 1 or 2, ensuring each group has at least two impressions.
Use conditional aggregation (e.g., MAX(CASE WHEN rn=1 THEN timestamp END) AS most_recent, MAX(CASE WHEN rn=2 THEN timestamp END) AS second_most_recent) grouped by user_id and ad_id.
Calculate the difference in seconds between the two timestamps, ensuring the result is positive (e.g., second_most_recent - most_recent or using TIMESTAMPDIFF).
Select user_id, ad_id, most_recent, second_most_recent, and the computed difference, filtering out any groups that do not have both timestamps.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.