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My first instinct was to just iterate through all the rules and check containment, which works but they pushed back immediately on efficiency.
Clarify the input format and semantics: rules are CIDR blocks with approve/reject tags, and the query is an IP or CIDR block. Use a binary trie (prefix tree) to store rules, where each node represents a bit of the IP address and holds the rule if a prefix ends there. For a query, traverse the trie along the bits of the query IP (or the first IP of the query CIDR) and keep track of the deepest node with a rule; that rule determines the decision, defaulting to reject if none found.
Pro tip: Discuss how to handle overlapping rules and the importance of longest-prefix match: mention that you can store the rule at the node where the prefix ends, and during traversal, update the best match whenever you encounter a rule. Also, consider edge cases like IPv4 vs IPv6, and whether the query CIDR should be checked against rules that cover it entirely or partially.
Ask about input formats (IPv4/IPv6, CIDR notation), whether rules can overlap, and how to handle a query CIDR that spans multiple rules. Confirm default behavior (reject if no match).
Propose a binary trie (prefix tree) where each level corresponds to a bit of the IP address. Each node can store a rule (approve/reject) if a prefix ends there. This allows efficient longest-prefix match.
For each rule, convert the CIDR to a bit string (e.g., 32 bits for IPv4). Traverse the trie, creating nodes as needed, and at the final node, store the rule. If multiple rules have the same prefix, the last one wins or handle conflict resolution.
For a query IP, traverse the trie bit by bit. Keep track of the deepest node that contains a rule. After traversal, the stored rule at that node is the decision. If no rule found, default to reject.
If the query is a CIDR block, decide whether to check all IPs in the block (inefficient) or interpret the query as a prefix and find the most specific rule that covers it. Discuss time complexity: O(32) for IPv4, O(128) for IPv6 per query, and space O(N*32) for N rules.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.