My first instinct was to just throw a standard sort at it and call it a day, but that felt too easy for Google.
Recognize that the array is 'k-sorted' and use a min-heap of size k+1 to efficiently extract the smallest element at each step. Iterate through the array, maintaining the heap, and place the extracted minimum into the sorted output. This achieves O(n log k) time and O(k) space, which is optimal for this problem.
Pro tip: Mention that for small k, this is nearly linear, and for k = n, it degrades to O(n log n) which is optimal for general sorting. Also, note that the heap approach is stable if needed by storing indices, but stability isn't required here.
Clarify that each element is at most K positions away from its sorted position, meaning the array is 'k-sorted'. This implies that the smallest element among the first K+1 elements must be the global minimum.
Use a min-heap to efficiently retrieve the minimum element among a sliding window of size K+1. The heap will contain at most K+1 elements at any time.
Initialize the heap with the first K+1 elements. Then, for each position from 0 to n-1, extract the minimum from the heap and place it in the sorted array. If there are remaining elements, add the next element from the array to the heap.
Building the initial heap takes O(K) time. Each of the n extract-min and insert operations takes O(log K) time, leading to O(n log K) overall. Space is O(K) for the heap.
Handle cases where K >= n (heap size n) or K = 0 (already sorted). For small K, the algorithm is nearly linear. Mention that if K is large, other sorting algorithms might be more suitable.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.