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DoorDash·Software Engineer·Onsite - Coding / Algorithms·Senior

SeniorPrefer not to say
May 2026

Summary

DoorDash software engineer coding round, one meaty algorithm question that spiraled into a bunch of follow-ups I was not fully prepared for. The core problem seemed familiar but the depth they wanted was something else.

Questions Asked (6)

Q1

Given an integer array that may contain negatives and duplicates, modify it in place to produce the next lexicographically greater arrangement. If no greater arrangement exists, wrap around to the smallest (ascending) order. Target O(n) time and O(1) space.

Algorithms & Data Structures
Author's notes

I knew the general shape of the algorithm going in, find the rightmost dip, swap with the next bigger element to the right, reverse the suffix.

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AI HintsAI Generated

Suggested Approach

This is the classic Next Permutation problem. The optimal O(n) time and O(1) space solution involves scanning from the right to find the first decreasing element, then swapping it with the smallest element to its right that is larger, and finally reversing the suffix to get the next lexicographically greater permutation. If no such element exists, simply reverse the entire array to wrap around to the smallest order.

Pro tip: Clearly explain why the algorithm is correct and why it achieves O(n) time and O(1) space, and mention edge cases like arrays with all duplicates or already sorted in descending order. This shows you understand the problem deeply and can communicate trade-offs.

1. Find the pivot

Scan the array from right to left to find the first index i where nums[i] < nums[i+1]. This is the pivot that needs to be increased. If no such index exists, the array is in descending order, so reverse the entire array to get the smallest permutation.

2. Find the successor

From the right, find the first element nums[j] that is greater than nums[i]. Since the suffix is non-increasing, this element is the smallest element greater than nums[i] in the suffix.

3. Swap pivot and successor

Swap nums[i] and nums[j]. This increases the prefix at the pivot to the next possible value.

4. Reverse the suffix

Reverse the subarray from i+1 to the end. This makes the suffix as small as possible (ascending order), yielding the next lexicographically greater permutation.

5. Handle wrap-around

If no pivot was found in step 1, reverse the entire array to get the smallest permutation (ascending order).

Key Points to Mention

  • Time complexity: O(n) because we perform at most two scans and one reversal.
  • Space complexity: O(1) because we modify the array in place without extra data structures.
  • Correctness: The algorithm finds the next permutation by minimally increasing the prefix and minimizing the suffix.
  • Edge cases: arrays with duplicates, all elements equal, already sorted ascending (next permutation), sorted descending (wrap around).
  • In-place modification: no additional arrays are used; swaps and reversals are done directly on the input.
  • Lexicographical order: the next greater arrangement is the smallest permutation that is greater than the current one.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Prove why this algorithm produces exactly the next arrangement without skipping any. Why does swapping the pivot with the correct neighbor and reversing the suffix guarantee correctness?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

This is where I started sweating.

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AI HintsAI Generated

Suggested Approach

Start by defining the problem: given a sequence, find the lexicographically next permutation. Then explain the algorithm's steps: find the longest non-increasing suffix (which is already the largest permutation of that suffix), identify the pivot just before it, swap the pivot with the smallest element in the suffix that is larger than it, and reverse the suffix to make it the smallest possible arrangement. Prove correctness by showing that any arrangement between the original and the next must share the same prefix up to the pivot, but the suffix after the pivot must be the smallest possible greater arrangement, which the swap and reverse achieve.

Pro tip: Emphasize that the suffix is non-increasing, so it's already the maximum permutation of those elements. This means the only way to get a larger permutation is to increase the pivot, and the smallest increase is achieved by swapping with the smallest larger element in the suffix. Reversing the suffix then minimizes it, ensuring no permutations are skipped.

1. Identify the longest non-increasing suffix

Explain that the suffix is already the largest permutation of its elements, so any larger permutation must involve changing an element before the suffix.

2. Find the pivot

The pivot is the element immediately before the suffix. It is the rightmost element that is smaller than its right neighbor, so swapping it with a larger element in the suffix will produce a larger permutation.

3. Swap with the smallest larger element

In the suffix, find the smallest element that is larger than the pivot. Swapping with it ensures the smallest possible increase at the pivot position, which is necessary for the next permutation.

4. Reverse the suffix

After the swap, the suffix remains non-increasing. Reversing it makes it non-decreasing, which is the smallest possible arrangement of those elements, thus minimizing the overall permutation.

5. Prove no permutations are skipped

Argue that any permutation between the original and the next must have the same prefix up to the pivot, but a larger element at the pivot, and a suffix that is the smallest possible. The algorithm constructs exactly that, so no intermediate permutations exist.

Key Points to Mention

  • Lexicographic order and next permutation definition
  • Longest non-increasing suffix property
  • Pivot selection: rightmost element smaller than its right neighbor
  • Swapping with the smallest larger element in the suffix
  • Reversing the suffix to get the smallest arrangement
  • Proof by contradiction: assume a permutation between original and next, show it must equal the next

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q3

How does your solution handle edge cases: duplicate values in the array, arrays already in descending order, single-element arrays, and empty arrays?

Algorithms & Data Structures
Author's notes

Duplicates tripped me up briefly.

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AI HintsAI Generated

Suggested Approach

Walk through each edge case systematically, explaining how your solution handles it without breaking correctness or performance. Emphasize that you considered these cases during design, and mention any trade-offs or additional checks needed. Conclude by summarizing how these edge cases validate the robustness of your approach.

Pro tip: Mention that you test edge cases explicitly and consider their impact on time/space complexity—this shows you think beyond just passing sample tests. Also, relate it to real-world scenarios (e.g., DoorDash order data) to demonstrate practical awareness.

1. Acknowledge the importance of edge cases

Start by stating that handling edge cases is crucial for a robust solution and that you proactively consider them during problem-solving.

2. Address each edge case individually

For each case (duplicates, descending order, single-element, empty), explain how your algorithm behaves and why it remains correct and efficient.

3. Discuss any modifications or special handling

If your solution requires adjustments (e.g., early returns, stability checks), describe them clearly and justify why they are necessary.

4. Analyze complexity implications

Explain whether these edge cases affect time or space complexity, and confirm that the worst-case bounds still hold.

5. Summarize and connect to real-world relevance

Conclude by reiterating that the solution is robust and mention how such edge cases might appear in practice (e.g., duplicate order IDs, already sorted data).

Key Points to Mention

  • Duplicates: ensure algorithm doesn't assume unique elements; stability if sorting.
  • Descending order: check if algorithm's performance degrades (e.g., quicksort worst-case) and how you mitigate it.
  • Single-element arrays: trivial case, but verify no out-of-bounds or unnecessary operations.
  • Empty arrays: handle gracefully with early return or base case to avoid errors.
  • Complexity: confirm that edge cases don't change Big-O bounds.
  • Testing: mention that you write unit tests for these cases.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q4

Does the algorithm change at all when the array contains negative numbers?

Algorithms & Data Structures
Author's notes

Short answer: no.

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AI HintsAI Generated

Suggested Approach

First, clarify which algorithm is being discussed (e.g., Kadane's, two-pointer, sliding window) and its assumptions. Then, explain how negative numbers affect the algorithm's logic, invariants, and edge cases, and describe any necessary modifications to handle them correctly.

Pro tip: Acknowledge that negative numbers often break greedy or sliding window approaches that assume monotonicity, and show you can adapt by resetting state or using prefix sums. This demonstrates deeper algorithmic insight and practical debugging skills.

1. Identify the algorithm and its assumptions

State the specific algorithm (e.g., Kadane's, two-pointer) and its typical assumptions, such as non-negative numbers or monotonic sums.

2. Analyze the impact of negatives

Explain how negative numbers can break the algorithm's logic, e.g., by invalidating greedy choices or causing sliding window sums to decrease.

3. Describe modifications or alternatives

Detail how to adjust the algorithm to handle negatives, such as resetting the current sum in Kadane's or using prefix sums with a hash map for subarray sum problems.

4. Discuss edge cases and complexity

Mention edge cases like all negatives or zeros, and confirm that the modified algorithm still meets time and space complexity requirements.

Key Points to Mention

  • Kadane's algorithm: reset current sum to 0 when it becomes negative, but handle all-negative arrays by initializing max to the first element.
  • Sliding window: negative numbers break the monotonic sum property, so two-pointer may not work; use prefix sums with a hash map instead.
  • Two-pointer techniques: may require sorting or different conditions when negatives are present.
  • Prefix sums: effective for subarray sum problems with negatives, often combined with a hash map for O(n) time.
  • Edge cases: all negative numbers, zeros, and large negative values affecting initialization.
  • Time/space complexity: ensure modifications do not degrade performance beyond O(n) time and O(1) or O(n) space.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q5

Generalize the solution so that 'next arrangement' is defined by a custom comparator rather than natural integer ordering. How would you adapt the algorithm?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Interesting follow-up.

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AI HintsAI Generated

Suggested Approach

Explain that the next permutation algorithm relies on comparing elements to find the pivot and successor, so generalizing it means replacing all direct comparisons with a custom comparator. Then outline the adapted steps: find the largest index i where comparator(a[i], a[i+1]) is true, find the largest index j > i where comparator(a[i], a[j]) is true, swap, and reverse the suffix using the comparator for ordering.

Pro tip: Emphasize that the algorithm's correctness depends on the comparator being a strict weak ordering; mention that if it's not, the result is undefined, showing you understand the underlying assumptions.

1. Identify comparison points

Locate every place in the standard next permutation algorithm where elements are compared (pivot search, successor search, and suffix reversal). These are the points that must use the custom comparator.

2. Replace comparisons with comparator

Substitute each direct comparison (e.g., a[i] < a[i+1]) with the custom comparator (e.g., comp(a[i], a[i+1])). Ensure the comparator defines a strict weak ordering.

3. Adapt pivot and successor search

Find the largest index i such that comp(a[i], a[i+1]) is true. Then find the largest index j > i such that comp(a[i], a[j]) is true. Swap a[i] and a[j].

4. Reverse suffix with comparator

Reverse the subarray from i+1 to the end. Since the suffix is sorted in descending order according to the comparator, reversing it yields ascending order, producing the next permutation.

5. Discuss complexity and edge cases

Note that time complexity remains O(n) and space O(1). Mention edge cases: last permutation (reverse whole array), duplicates, and comparator stability.

Key Points to Mention

  • The algorithm's logic is independent of the comparison operator; only the comparisons need to be abstracted.
  • A custom comparator must be a strict weak ordering (irreflexive, transitive, and transitive on incomparability) for the algorithm to work correctly.
  • The pivot is the largest index i where comp(a[i], a[i+1]) is true; if none, the sequence is the last permutation.
  • The successor is the largest index j > i where comp(a[i], a[j]) is true; swapping them maintains the property that the suffix is non-increasing.
  • Reversing the suffix after the swap produces the next permutation in the custom order.
  • Time and space complexity remain O(n) and O(1) respectively, as the comparator is called a constant number of times per element.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q6

For very large arrays, what are the practical performance considerations around memory access patterns? And walk me through a test suite you'd write for this.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

The cache behavior angle was a small surprise.

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AI HintsAI Generated

Suggested Approach

Start by explaining how memory access patterns (sequential vs. random) affect cache performance and overall runtime for large arrays. Then, outline a test suite that measures these effects, including benchmarks for different access patterns and array sizes, and validates correctness. Emphasize practical trade-offs and how you'd use profiling to guide optimizations.

Pro tip: Mention that you'd use hardware performance counters (e.g., cache misses) to quantify the impact, and that you'd consider the memory hierarchy (L1/L2/RAM) when designing tests. This shows depth beyond just timing.

1. Explain memory hierarchy and access patterns

Describe how CPUs cache data and why sequential access is faster than random access due to spatial locality. Mention cache lines and prefetching.

2. Discuss practical implications for large arrays

Explain that for arrays exceeding cache size, access patterns dominate performance. Give examples like iterating row-major vs. column-major in 2D arrays.

3. Outline test suite goals

State that the test suite should measure performance differences, validate correctness, and be reproducible. It should cover various array sizes and access patterns.

4. Detail test cases and metrics

List specific tests: sequential vs. random access, strided access, different data types, and multi-threaded scenarios. Include metrics like execution time, cache misses, and memory bandwidth.

5. Describe tooling and analysis

Mention using profilers (perf, VTune) and microbenchmarking frameworks (Google Benchmark). Explain how to interpret results and iterate on optimizations.

Key Points to Mention

  • Cache locality and its impact on performance
  • Sequential vs. random access patterns
  • Cache line size and prefetching
  • Strided access and its effect on cache utilization
  • Use of hardware performance counters (e.g., cache misses)
  • Benchmarking tools and methodologies (e.g., Google Benchmark, perf)

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.