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Salesforce·Software Engineer·Technical Phone Screen·Senior

SeniorPrefer not to say
Apr 2026Remote

Summary

Salesforce software engineer interview that went deep into number theory territory. The main problem was implementing Non-Adjacent Form (NAF) representation for integers, which I genuinely had not thought about since a cryptography elective years ago. It was a lot more involved than a typical coding round.

Questions Asked (4)

Q1

Implement a function toNAF(n) that converts an integer n (including negatives) to its Non-Adjacent Form using digits from {-1, 0, 1}, where no two adjacent digits are both nonzero, returning the result least-significant-first. Also implement fromNAF(digits) to convert back to the original integer.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

I knew what NAF was in theory but writing the actual algorithm under pressure was a different story.

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AI HintsAI Generated

Suggested Approach

Explain the NAF algorithm: repeatedly divide n by 2, but if n is odd, choose the remainder (1 or -1) that makes the quotient even, ensuring no adjacent nonzeros. For fromNAF, compute the sum of digit * 2^i. Emphasize handling negatives and returning least-significant-first.

Pro tip: Mention that NAF minimizes the number of nonzero digits, which is useful in cryptography (e.g., elliptic curve scalar multiplication) for efficiency. Also, note that the algorithm works for negative n by using floor division and adjusting the remainder.

1. Clarify requirements and edge cases

Confirm that digits are least-significant-first and that n can be negative. Discuss edge cases like n=0, n=1, and negative numbers.

2. Design toNAF algorithm

Use a loop: while n != 0, if n is odd, compute r = 2 - (n mod 4) to get 1 or -1, then n = n - r; else r = 0. Append r to digits, then n = n // 2. This ensures no adjacent nonzeros.

3. Design fromNAF algorithm

Iterate over digits with index i, compute sum += digit * (2**i). Return the sum.

4. Test with examples

Test with positive, negative, and zero values. Verify that fromNAF(toNAF(n)) == n and that no two adjacent digits are both nonzero.

5. Discuss trade-offs and optimizations

Mention time complexity O(log n) and space O(log n). Compare with binary representation and note NAF's minimal weight property.

Key Points to Mention

  • NAF ensures no two adjacent nonzero digits, which minimizes the number of nonzero digits.
  • Handling negative n: use floor division and adjust remainder to keep quotient even when n is odd.
  • The algorithm for toNAF: if n is odd, choose r = 2 - (n mod 4) to get 1 or -1; else r = 0.
  • fromNAF is a simple weighted sum: sum(digit * 2^i).
  • Time and space complexity: O(log n) for both functions.
  • Applications: efficient exponentiation and elliptic curve cryptography.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Prove that the NAF representation is correct and explain why it minimizes the number of nonzero digits among all signed-binary representations of an integer.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

This is where things got uncomfortable.

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AI HintsAI Generated

Suggested Approach

Start by defining NAF and the signed-binary representation, then prove correctness by showing the algorithm produces a valid representation with no two adjacent nonzeros. To prove minimality, use a weight argument: assign each nonzero digit a weight based on its position and show any representation with fewer nonzeros would violate the no-adjacent-nonzeros property or the value constraint.

Pro tip: Emphasize that NAF is unique and that the no-adjacent-nonzeros property is key to minimality; mention that this is why NAF is used in elliptic curve cryptography for efficient scalar multiplication.

1. Define NAF and signed-binary representation

Clearly state what a signed-binary representation is (digits in {-1,0,1}) and define NAF as the unique representation with no two adjacent nonzeros. Mention that NAF is computed by repeatedly dividing by 2 and adjusting remainders to -1, 0, or 1.

2. Prove correctness of the NAF algorithm

Show that the algorithm terminates and produces a valid representation equal to the original integer. Argue that the no-adjacent-nonzeros property holds by construction: when a remainder of 1 is chosen, the next quotient becomes even, ensuring the next digit is zero.

3. Establish minimality via weight argument

Assign a weight to each nonzero digit: for a digit at position i, weight = 2^i. Show that any signed-binary representation with fewer nonzeros would require a nonzero at a position where NAF has a zero, leading to a contradiction with the no-adjacent-nonzeros property or the value constraint.

4. Conclude uniqueness and minimality

Summarize that NAF is the unique representation with no adjacent nonzeros, and that this property directly implies it has the minimal number of nonzeros among all signed-binary representations.

Key Points to Mention

  • Definition of signed-binary representation and NAF
  • Algorithm for computing NAF (e.g., while n > 0: if n odd, digit = 2 - (n mod 4), else 0; n = (n - digit)/2)
  • Proof that NAF has no two adjacent nonzeros
  • Weight argument for minimality: each nonzero contributes at least 2^i, and non-adjacency forces a lower bound on the number of nonzeros
  • Uniqueness of NAF
  • Application in cryptography (e.g., efficient scalar multiplication in ECC)

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q3

Analyze the time and space complexity of your toNAF and fromNAF implementations, and discuss edge cases like n = 0 and very large magnitudes.

Algorithms & Data Structures
Author's notes

Went fine.

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AI HintsAI Generated

Suggested Approach

First, define what NAF (Non-Adjacent Form) is and how your toNAF and fromNAF functions work, then analyze their time and space complexity in terms of the number of bits in the input. Finally, discuss edge cases such as n = 0, negative numbers, and very large magnitudes, explaining how your implementation handles them and any potential pitfalls.

Pro tip: Mention that NAF is unique and has minimal weight, which is why it's used in cryptography; also note that the average density of non-zero digits is 1/3, which can affect performance in practice.

1. Define NAF and implementation overview

Briefly explain that NAF is a signed binary representation with no two adjacent non-zero digits, and describe your toNAF and fromNAF algorithms at a high level.

2. Analyze time complexity

State that both toNAF and fromNAF run in O(k) time, where k is the number of bits in the input, because they process each bit once.

3. Analyze space complexity

Explain that the space complexity is O(k) for the output array (or O(1) extra space if modifying in place), and note that the output length is at most k+1 digits.

4. Discuss edge cases

Cover n = 0 (should return an empty array or a single zero digit), negative numbers (NAF can represent them, but clarify if your implementation handles sign separately), and very large magnitudes (e.g., arbitrary precision integers, where k can be huge, but complexity remains linear).

5. Conclude with practical implications

Summarize that the algorithms are efficient and suitable for cryptographic applications, and mention any optimizations or alternative representations if relevant.

Key Points to Mention

  • NAF is a unique signed-digit representation with digits in {-1, 0, 1} and no adjacent non-zero digits.
  • Time complexity is O(k) for both toNAF and fromNAF, where k is the number of bits.
  • Space complexity is O(k) for the output, but can be O(1) extra if computed in place.
  • Edge case n = 0: typically returns an empty array or [0]; ensure fromNAF handles it correctly.
  • Negative numbers: NAF can represent them, but often sign is handled separately; clarify your implementation.
  • Very large magnitudes: complexity remains linear in the number of bits, but watch for integer overflow in fixed-width types.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q4

As an extension: how would you use the NAF representation of k to compute n * k more efficiently, reducing the number of additions needed?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Actually enjoyed this part.

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AI HintsAI Generated

Suggested Approach

Explain that NAF (Non-Adjacent Form) represents k with digits in {-1, 0, 1} and no two consecutive non-zero digits, minimizing the number of non-zero digits. Then describe how to compute n*k by iterating through the NAF digits from most significant to least, doubling the accumulator and adding or subtracting n based on the digit, which reduces the number of additions/subtractions compared to binary.

Pro tip: Mention that NAF is especially beneficial in elliptic curve cryptography for scalar multiplication, and that the average density of non-zero digits is 1/3, leading to about 1/3 fewer additions than binary. Also note that the trade-off is the need to precompute the NAF representation, which is cheap.

1. Define NAF

State that NAF is a signed binary representation with digits in {-1, 0, 1} and no two consecutive non-zero digits, and that it has minimal weight among all signed binary representations.

2. Convert k to NAF

Explain the algorithm to compute NAF: repeatedly divide k by 2, and if k is odd, choose the remainder as 1 or -1 to make the quotient even, ensuring no adjacent non-zero digits.

3. Compute n*k using NAF

Iterate through the NAF digits from most significant to least: for each digit, double the accumulator; if digit is 1, add n; if digit is -1, subtract n; if 0, do nothing.

4. Analyze efficiency

Compare the number of additions/subtractions: binary uses about (bit length)/2 additions on average, while NAF uses about (bit length)/3, reducing operations by roughly 1/6 of the bit length.

5. Discuss trade-offs

Mention that NAF requires precomputing the representation and handling negative digits, but the reduction in additions is beneficial for performance-critical applications like cryptography.

Key Points to Mention

  • NAF has digits in {-1, 0, 1} and no two consecutive non-zero digits.
  • The average density of non-zero digits in NAF is 1/3, compared to 1/2 in binary.
  • Computing n*k with NAF uses double-and-add/subtract: double for each digit, add or subtract n for non-zero digits.
  • The number of additions/subtractions is reduced by about 1/6 of the bit length compared to binary.
  • NAF is particularly useful in elliptic curve scalar multiplication for efficiency.
  • The trade-off is the overhead of computing the NAF representation, which is negligible for large k.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.