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Start by clarifying the problem and constraints, then propose a modified binary search that handles duplicates and finds both the rotation point and the leftmost target index. Walk through the algorithm, prove correctness, analyze time/space complexity, and discuss edge cases with thorough unit tests.
Pro tip: Emphasize that duplicates can degrade performance to O(n) in the worst case, and mention that you would confirm with the interviewer whether the array is guaranteed to be rotated at least once or could be unrotated.
Ask about input size, whether the array can be empty, if rotation is guaranteed, and if duplicates affect the definition of rotation point. Confirm the expected return format for both indices.
Describe a two-phase binary search: first find the rotation point (smallest element) using a modified binary search that handles duplicates, then find the leftmost occurrence of the target in the appropriate sorted subarray.
Argue that the rotation point is the only index where the previous element is greater, and that binary search on the correct subarray finds the leftmost target. State time complexity: O(log n) average, O(n) worst-case with duplicates; space O(1).
List test cases: empty array, single element, all equal, no rotation, rotation at various points, target at rotation point, target spanning boundary, target absent, duplicates causing worst-case.
Mention alternative approaches (e.g., linear scan for small arrays), handling of duplicates by shrinking search space, and potential to combine both searches into one pass if needed.
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