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Instacart·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Apr 2026

Summary

Instacart SWE interview with a scheduling/queueing problem that started simple and got progressively harder. The follow-ups on multi-clerk scaling are where things got real.

Questions Asked (3)

Q1

Given n grocery pickup orders, each with an arrival time and a service duration, compute the average waiting time for all shoppers. The clerk processes one order at a time and waits if idle. Arrival times may need to be sorted first.

Algorithms & Data Structures
Author's notes

The single-clerk version felt manageable.

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AI HintsAI Generated

Suggested Approach

Sort the orders by arrival time, then simulate the clerk's process by tracking the current time and accumulating each order's waiting time. Compute the average by dividing the total waiting time by n, and discuss time/space complexity.

Pro tip: Clarify edge cases upfront (e.g., empty input, simultaneous arrivals) and mention that sorting is O(n log n) while the simulation is O(n), showing you consider both correctness and efficiency.

1. Clarify and Define

Confirm the input format, waiting time definition (time from arrival to start of service), and edge cases like n=0 or simultaneous arrivals.

2. Sort by Arrival Time

Sort the orders by arrival time to process them in chronological order, ensuring the simulation is correct.

3. Simulate Service

Iterate through sorted orders, maintaining current time. For each order, update current time to max(current time, arrival time), add waiting time (current time - arrival time), then add service duration.

4. Compute Average

Sum all waiting times and divide by n to get the average. Handle n=0 by returning 0 or as specified.

5. Analyze Complexity

State that sorting takes O(n log n) and simulation takes O(n), so overall O(n log n) time and O(1) extra space (if sorting in place).

Key Points to Mention

  • Sorting orders by arrival time is necessary for correct simulation.
  • Waiting time is defined as start of service minus arrival time.
  • Use a running clock (current time) that updates to max(current time, arrival time) before adding service duration.
  • Handle edge cases: n=0, simultaneous arrivals, and orders arriving before the clerk is free.
  • Time complexity: O(n log n) due to sorting; space complexity: O(1) or O(n) depending on sort.
  • Average waiting time is total waiting time divided by n.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Extend the solution to k identical clerks. Each arriving order goes to whichever clerk becomes free the earliest. Return the average waiting time and justify your choice of data structures and the time complexity.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

This is where I had to actually think.

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AI HintsAI Generated

Suggested Approach

Model the problem as a min-heap of clerk availability times, where each order is assigned to the clerk with the earliest free time. For each order, pop the earliest clerk, compute the waiting time, update the clerk's next availability, and push back into the heap. Sum waiting times and divide by number of orders to get the average.

Pro tip: Explicitly compare the heap approach with alternatives like sorting or balanced BSTs, highlighting that the heap gives O(log k) per order and is optimal for dynamic earliest-free assignment. Also mention that if orders arrive in sorted order by time, a heap is still efficient, but if k is small, a linear scan might be simpler.

1. Understand the problem and constraints

Clarify that orders arrive over time, each clerk processes one order at a time, and we need to assign each order to the clerk who becomes free earliest. Confirm whether arrival times are given and if orders are processed in arrival order.

2. Choose data structures

Use a min-heap (priority queue) to store the next available time for each clerk. This allows O(log k) retrieval of the earliest free clerk and O(log k) update after assigning an order.

3. Simulate the process

Iterate through orders in arrival order. For each order, pop the clerk with the smallest available time, compute waiting time as max(0, clerk_free_time - order_arrival_time), update clerk_free_time to max(order_arrival_time, clerk_free_time) + service_time, and push back.

4. Compute average waiting time

Accumulate total waiting time and divide by the number of orders. Return the average as a float.

5. Analyze time and space complexity

Time complexity is O(n log k) for n orders and k clerks, since each order involves one heap pop and push. Space complexity is O(k) for the heap.

Key Points to Mention

  • Min-heap (priority queue) is the optimal data structure for dynamically selecting the clerk with the earliest free time.
  • Time complexity: O(n log k) where n is number of orders and k is number of clerks.
  • Space complexity: O(k) for the heap.
  • Waiting time calculation: max(0, clerk_free_time - order_arrival_time).
  • Update clerk availability: max(order_arrival_time, clerk_free_time) + service_time.
  • Alternative approaches: linear scan O(nk) or sorting if orders are not in arrival order, but heap is more efficient for large k.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q3

How does your approach scale for very large n, say up to 200,000 orders? What are the time and space complexities?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Sorting is O(n log n) if arrivals aren't pre-sorted.

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AI HintsAI Generated

Suggested Approach

Start by restating the problem and clarifying constraints (e.g., order size, memory limits). Then analyze the current algorithm's time and space complexity, identify bottlenecks, and propose optimizations (e.g., streaming, indexing, or distributed processing) to handle 200,000 orders. Conclude with the optimized complexities and trade-offs.

Pro tip: Quantify the impact: show that 200,000 orders is manageable with O(n log n) time and O(n) space, but if the current solution is O(n²), it would be infeasible. Mention that you'd validate with a quick back-of-the-envelope calculation and consider real-world factors like I/O and network latency.

1. Clarify requirements and constraints

Ask about the expected order size, memory limits, and whether the data fits in memory. Confirm if the solution needs to be real-time or batch.

2. Analyze current complexity

State the time and space complexity of your current approach. Identify the dominant operations (e.g., sorting, nested loops) and how they scale with n.

3. Propose optimizations

Suggest algorithmic improvements (e.g., using hash maps, heaps, or divide-and-conquer) or system-level changes (e.g., streaming, sharding) to reduce complexity.

4. State optimized complexities

Provide the new time and space complexities after optimization. Explain why they are suitable for n=200,000 (e.g., O(n log n) is fine, O(n²) is not).

5. Discuss trade-offs and validation

Mention trade-offs (e.g., memory vs. speed) and how you would test with large datasets, including edge cases and performance benchmarks.

Key Points to Mention

  • Time complexity: O(n log n) for sorting-based approaches, O(n) for hash-based, and why O(n²) is unacceptable for n=200,000.
  • Space complexity: O(n) is acceptable if memory allows; otherwise, consider external sorting or streaming.
  • Data structures: hash maps for O(1) lookups, heaps for top-k, or tries for prefix matching.
  • Scalability techniques: sharding, batch processing, or using distributed systems like MapReduce.
  • Real-world constraints: I/O bottlenecks, network latency, and memory limits in production.
  • Validation: back-of-the-envelope calculations and load testing with synthetic data.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.