I went greedy first, kept throwing budget at whatever the current bottleneck was.
Recognize that the problem is to maximize the minimum throughput across services given a budget for scaling. Use binary search on the target throughput T, and for each T, check if the total cost to bring all services up to at least T is within budget. The answer is the largest feasible T.
Pro tip: Clarify that scaling costs are linear and that we can scale each service independently; then emphasize that binary search is optimal because the feasibility predicate is monotonic. Also mention that if costs are not linear, the approach may need adjustment.
Restate the problem: we have n services in series, each with initial throughput t_i and cost per unit increase c_i. Given budget B, maximize min_i (t_i + x_i) where x_i >= 0 and sum(c_i * x_i) <= B.
For a candidate throughput T, compute the required scaling for each service: if t_i < T, need x_i = T - t_i, costing c_i*(T - t_i). Sum these costs and check if <= B.
Binary search on T between min(t_i) and min(t_i) + B / min(c_i) (or a safe upper bound). For each mid, run the feasibility check. If feasible, search higher; else search lower.
Consider cases where budget is insufficient to scale any service, or where scaling one service is much cheaper. Analyze time complexity: O(n log(range)) and space O(1).
Mention that if costs are not linear, we might need a different approach (e.g., greedy or DP). Also discuss whether we can scale down services (not needed here) and the impact of discrete scaling.
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