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Airbnb·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
May 2026

Summary

Airbnb SWE interview with a classic graph/BFS problem. Not much context given about how it went but the problem itself is a well-known one if you've done any serious algo prep.

Questions Asked (1)

Q1

Given two strings and a dictionary of valid words, find the minimum number of operations needed to transform the first string into the second, where each intermediate step must be a valid dictionary word.

Algorithms & Data Structures
Author's notes

Word ladder.

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AI HintsAI Generated

Suggested Approach

Model the problem as finding the shortest path in an unweighted graph where nodes are dictionary words and edges connect words that differ by one character. Use BFS from the start word to the end word, ensuring each intermediate word is in the dictionary. If the end word is not in the dictionary, return 0 or -1 as appropriate.

Pro tip: Preprocess the dictionary into a set for O(1) lookups, and generate neighbors by trying all 26 lowercase letters at each position. This avoids O(N^2) pairwise comparisons and is the expected efficient solution.

1. Clarify requirements and edge cases

Confirm that each operation changes exactly one character, and that all intermediate words must be in the dictionary. Ask about cases where start or end word is not in the dictionary, or when no transformation is possible.

2. Model as a graph problem

Treat each dictionary word as a node, with edges between words that differ by one character. The goal is to find the shortest path from start to end, which corresponds to the minimum number of operations.

3. Choose BFS for shortest path

Since edges are unweighted, BFS guarantees the shortest path. Initialize a queue with the start word and a visited set to avoid cycles.

4. Optimize neighbor generation

Instead of comparing all pairs, generate neighbors by changing each character to 'a'-'z' and checking if the result is in the dictionary set. This reduces time complexity to O(L * 26 * N) where L is word length and N is dictionary size.

5. Analyze complexity and discuss trade-offs

State time and space complexity, and mention alternative approaches like bidirectional BFS for further optimization. Discuss handling of large dictionaries and potential memory constraints.

Key Points to Mention

  • Graph modeling: words as nodes, one-character differences as edges
  • BFS for shortest path in unweighted graph
  • Using a set for O(1) dictionary lookups
  • Generating neighbors by trying all 26 letters at each position
  • Handling edge cases: start/end not in dictionary, no path exists
  • Time and space complexity analysis, and possible optimizations like bidirectional BFS

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.