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My first instinct was to BFS from every open cell individually and that would've been a disaster at 300x300.
Use multi-source BFS starting from all transit stations simultaneously to compute shortest distances to all reachable open streets. Initialize a distance matrix with -1, set transit stations to 0, and enqueue them; then BFS outward, updating distances for unvisited open streets. Buildings and unreachable cells remain -1.
Pro tip: Clarify edge cases upfront (e.g., no transit stations, all buildings) and mention that multi-source BFS is optimal because it processes each cell once, achieving O(R*C) time. Also, discuss memory optimization by using a 2D array for distances and a queue for BFS.
Clarify that the grid contains open streets (0), buildings (1), and transit stations (2). The goal is to return a grid of same dimensions where each open street cell contains the minimum moves to the nearest transit station, and buildings or unreachable cells are -1.
Explain that multi-source BFS from all transit stations simultaneously computes shortest distances efficiently. This avoids running BFS from each open street, which would be less efficient.
Create a distance matrix initialized to -1. Enqueue all transit station coordinates and set their distance to 0. Use a queue for BFS.
While the queue is not empty, dequeue a cell, and for each of its four neighbors, if the neighbor is within bounds, is an open street, and has distance -1, set its distance to current distance + 1 and enqueue it.
After BFS completes, the distance matrix contains the minimum moves for each open street, with -1 for buildings and unreachable cells. Return this matrix.
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