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Saw 'coins' and immediately started thinking greedy, which is the wrong instinct here.
Recognize this as a coin change problem with overpayment allowed, which can be modeled as finding the minimum number of coins to represent n plus some overpayment amount, where the change is also given in the same denominations. Use dynamic programming to compute the minimum coins for all amounts up to a reasonable bound, then for each n, consider overpaying up to that bound and add the coins for the change. Alternatively, derive a greedy strategy by analyzing the denominations and proving that the optimal solution uses at most one coin of each denomination in the change, leading to a simple formula.
Pro tip: Demonstrate maturity by discussing the trade-offs between a brute-force DP solution and a more elegant greedy approach, and mention that the greedy approach works because the denominations are canonical (each is a multiple of the previous).
Clarify that you can pay any amount ≥ n, and the change is returned using the same coin denominations. The goal is to minimize the total number of coins used in payment plus change.
For a given n, consider all possible overpayment amounts m ≥ n, and compute the minimum coins to make m plus the minimum coins to make m - n. The answer is the minimum over m.
Use dynamic programming to compute min coins for all amounts up to a bound (e.g., n + 200). Alternatively, exploit the canonical coin system to derive a greedy formula.
If using DP, note that the bound can be limited because overpaying more than the largest denomination is never beneficial. If using greedy, prove that the optimal solution uses at most one coin of each denomination in the change.
Test with small examples (e.g., n=3, n=8, n=99) to verify the approach and ensure edge cases are handled.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.