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Blanked for a second because I kept trying to assign the sums to specific pairs before setting up the algebra.
Let the pairwise sums be x = a+b, y = a+c, z = b+c. Solve the system of equations to find a, b, c in terms of x, y, z, then substitute the given values and identify the largest number. Alternatively, note that the sum of all pairwise sums is 2(a+b+c), so compute a+b+c and subtract each pairwise sum to get the individual numbers.
Pro tip: After solving, verify that the pairwise sums of your numbers match the given values in some order. This quick check catches arithmetic errors and demonstrates rigor.
Let the pairwise sums be x = a+b, y = a+c, z = b+c, where x, y, z are 39, 48, 51 in some order.
Observe that (a+b) + (a+c) + (b+c) = 2(a+b+c). So compute the total sum S = a+b+c = (x+y+z)/2.
Subtract each pairwise sum from S: a = S - (b+c) = S - z, b = S - y, c = S - x. This gives the three numbers directly.
Plug in the given values: S = (39+48+51)/2 = 69. Then a = 69-51=18, b=69-48=21, c=69-39=30. The largest is 30.
Check that the pairwise sums of 18, 21, 30 are 39, 48, 51: 18+21=39, 18+30=48, 21+30=51. Correct.
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