I jumped straight to Kahn's algorithm and felt good about it, but then they asked why my output differed from theirs on the example and I realized I was using a regular queue instead of a min-heap.
Model the tasks and dependencies as a directed graph and use Kahn's algorithm for topological sorting. To ensure the smallest label is picked when multiple tasks are ready, use a min-heap (priority queue) to select the next task. If the number of processed tasks is less than n, a cycle exists, so return an empty list.
Pro tip: Mention that using a min-heap instead of a regular queue ensures the lexicographically smallest topological order, which is a common follow-up requirement. Also, discuss how you would handle large inputs by using efficient data structures and avoiding recursion to prevent stack overflow.
Restate the problem to ensure you understand the dependency representation and the tie-breaking rule. Ask about input size, whether dependencies are given as pairs, and if the graph is guaranteed to be a DAG.
Create an adjacency list for the graph and an array to track in-degrees of each task. For each dependency [a, b], add b to a's adjacency list and increment b's in-degree.
Scan the in-degree array and push all tasks with in-degree 0 into a min-heap (priority queue) to always extract the smallest label first.
While the heap is not empty, pop the smallest task, add it to the result order, and for each neighbor, decrement its in-degree. If a neighbor's in-degree becomes 0, push it into the heap.
After processing, if the result order contains all n tasks, return it; otherwise, a cycle exists, so return an empty list.
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