Recognized it as a variant of the island perimeter problem pretty fast, which helped.
Use BFS/DFS to traverse each island, computing its perimeter by counting water/boundary edges for each land cell. Track the maximum perimeter across all islands. Discuss trade-offs between DFS recursion depth and BFS queue memory.
Pro tip: Mention that you can compute perimeter during traversal without extra space by checking each cell's four neighbors, and highlight the importance of handling large grids with iterative BFS to avoid stack overflow.
Restate the problem to ensure understanding: 4-connected islands, perimeter definition, and edge cases like empty grid or no land. Ask about grid size constraints to discuss scalability.
Decide between DFS and BFS. DFS is simpler but may cause stack overflow for large islands; BFS uses a queue and is safer for deep recursion. Mention iterative DFS as an alternative.
During traversal, for each land cell, check its four neighbors. If a neighbor is water or out of bounds, increment perimeter. Avoid revisiting cells by marking them visited.
Maintain a global max perimeter. After traversing each island, update max. Handle edge cases: all water (return 0), single cell (perimeter 4), and multiple islands.
Time complexity O(m*n) since each cell visited once. Space complexity O(m*n) for visited set or queue. Discuss potential optimizations like modifying grid in-place to mark visited.
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