My first instinct was to sort the odd digits in ascending order and concatenate them, which works, but I spent too long second-guessing whether leading zeros could appear or whether the result should be zero if there are no odd digits at all.
Clarify the problem constraints and edge cases, then propose an efficient algorithm that extracts odd digits, sorts them in ascending order, and handles leading zeros. Discuss time and space complexity, and consider alternative approaches like counting sort for digits.
Pro tip: Mention that since digits are 0-9, a counting sort (frequency array) gives O(n) time, which is optimal. Also, explicitly handle the case where no odd digits exist by returning -1 or 0 as per requirements.
Ask about input type (integer or string), output format, and behavior when no odd digits are present. Confirm if leading zeros are allowed (they are not, as the number would be smaller without them).
Iterate through the digits of the input number and collect all odd digits (1,3,5,7,9). This can be done by modulo 10 and division, or by converting to string.
Sort the collected odd digits in non-decreasing order to form the smallest possible number. Use counting sort (frequency array of size 10) for O(n) time, or built-in sort for O(n log n).
Concatenate the sorted digits. Since all digits are odd, there are no zeros, so no leading zero issue. If no odd digits, return -1 or 0 as agreed.
State time complexity O(n) with counting sort, space O(1) (fixed size array). Walk through examples like 12345 -> 135, and edge cases like 2468 (no odd digits) and 97531 -> 13579.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.