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LinkedIn·Software Engineer·Technical Phone Screen·Senior

Senior
Jun 2026

Summary

LinkedIn SWE interview with a pretty involved BST problem that had a lot of moving parts. The core question was straightforward to state but the complexity constraints made it genuinely tricky to nail down cleanly.

Questions Asked (2)

Q1

Given a BST with n nodes and a real-valued target t, find k node values closest to t. Your solution must run in O(log n + k) expected time and use only O(h) extra space where h is the tree height. You can use predecessor/successor iterators backed by in-order stacks, or a recursive approach. Also handle tie-breaking, the case where k > n, and duplicate values.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

This one took me a minute to even parse.

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AI HintsAI Generated

Suggested Approach

Start by locating the node with the value closest to t using a standard BST search in O(log n) time, then expand outward using two in-order iterators (predecessor and successor) to collect the k closest values. Compare the next predecessor and successor values, picking the one closer to t, until k values are collected or both iterators are exhausted. Handle edge cases like k > n, duplicates, and tie-breaking by defining a consistent rule (e.g., prefer smaller value on tie).

Pro tip: Emphasize that the O(h) space comes from the two stacks used by the iterators, and that the expected O(log n + k) time relies on the BST being balanced; if the tree is skewed, the search could degrade to O(n). Also, explicitly state your tie-breaking rule and how you handle duplicates to show attention to detail.

1. Clarify requirements and edge cases

Confirm the definition of 'closest' (absolute difference), tie-breaking rule (e.g., prefer smaller value), and how to handle k > n (return all nodes) and duplicates (treat as separate nodes).

2. Locate the closest node

Perform a BST search to find the node with value closest to t, keeping track of the best candidate and its difference. This takes O(log n) expected time.

3. Initialize predecessor and successor iterators

Set up two in-order iterators: one for predecessors (values <= closest) and one for successors (values >= closest). Each iterator uses a stack of size O(h).

4. Expand outward to collect k closest values

Repeatedly compare the next predecessor and successor values, pick the one with smaller absolute difference to t, and add it to the result. Continue until k values are collected or both iterators are exhausted.

5. Handle ties and duplicates

When differences are equal, apply the tie-breaking rule (e.g., choose the smaller value). For duplicates, ensure each occurrence is considered separately, possibly by advancing the iterator past equal values.

Key Points to Mention

  • Time complexity: O(log n + k) expected, assuming a balanced BST; worst-case O(n) if skewed.
  • Space complexity: O(h) due to the two stacks used by the iterators, where h is the tree height.
  • Use of predecessor/successor iterators backed by in-order stacks to traverse the tree in sorted order without extra space beyond the stacks.
  • Tie-breaking rule: define a consistent rule (e.g., prefer smaller value) and apply it when differences are equal.
  • Handling k > n: return all n nodes, and ensure the algorithm terminates gracefully.
  • Duplicates: treat each node as a separate entity; the iterators will naturally yield duplicates in order.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

How would you adapt your solution if the tree were a general binary tree instead of a BST? What changes in terms of approach and complexity guarantees?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Honestly the follow-up I was least prepared for.

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AI HintsAI Generated

Suggested Approach

First, clarify the original problem and solution for a BST, then explain how the approach changes for a general binary tree, focusing on the loss of ordering properties. Finally, discuss the impact on time and space complexity, and any trade-offs or alternative strategies.

Pro tip: Emphasize that while BSTs allow O(log n) operations, general binary trees often require O(n) traversal, but you can still optimize by using techniques like recursion with pruning or iterative traversals. Mention that the choice of traversal (pre-order, in-order, post-order) depends on the specific problem.

1. Restate the original BST solution

Briefly describe the algorithm and its complexity for a BST, highlighting how the BST property enables efficient search, insertion, or deletion.

2. Identify the impact of removing BST property

Explain that without ordering, you cannot make assumptions about node values, so you must potentially visit all nodes, leading to O(n) time in the worst case.

3. Adapt the algorithm for a general binary tree

Describe how to modify the approach, such as using a full traversal (e.g., DFS or BFS) and possibly additional data structures (e.g., hash map) to achieve the goal.

4. Analyze new complexity guarantees

State the new time and space complexity, noting that time becomes O(n) and space may be O(n) for recursion or auxiliary structures, and discuss if any optimizations are possible.

5. Discuss trade-offs and alternatives

Mention any trade-offs (e.g., time vs. space) and alternative approaches (e.g., iterative vs. recursive) that might be more suitable for a general binary tree.

Key Points to Mention

  • Loss of BST property means no guaranteed ordering, so search operations degrade to O(n).
  • Traversal techniques (DFS, BFS) become essential for exploring all nodes.
  • Additional data structures like hash maps or sets may be needed to track visited nodes or store values.
  • Time complexity changes from O(log n) to O(n) in the worst case; space complexity may also increase.
  • Recursive solutions may cause stack overflow for deep trees; iterative approaches with explicit stacks/queues are safer.
  • The specific problem (e.g., search, insert, delete, validation) dictates the best adaptation; always clarify the problem first.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.