← Amazon Interview Insights

Amazon·Software Engineer·Technical Phone Screen·Intermediate

IntermediatePrefer not to say
May 2026

Summary

Amazon SWE interview with a data structure design problem that felt straightforward on the surface but had a sneaky efficiency constraint baked in. One question, decent amount of back-and-forth on the complexity side.

Questions Asked (1)

Q1

Design a class to track users who have logged in exactly once on a shopping platform. The class needs two methods: one to record a login event given a username, and another to return the username of the earliest such single-visit user (or null if none exist). Both operations should be efficient.

Algorithms & Data StructuresSystem DesignTechnical Trade-offs
Author's notes

My first instinct was a hashmap from username to login count, which covers the counting part fine.

Create a free account to read the full note

AI HintsAI Generated

Suggested Approach

Clarify the requirements and constraints, then propose a solution using a hash map to track login counts and a queue or linked list to maintain the order of single-visit users. Discuss time and space complexity, and consider edge cases and potential optimizations.

Pro tip: Demonstrate awareness of real-world concerns like concurrency and scalability, and mention how you would handle them in a production environment.

1. Clarify Requirements

Ask questions to confirm details: What defines a 'login event'? Should the earliest single-visit user be based on the time of their first login? Are usernames unique? What are the expected scale and performance requirements?

2. Design Data Structures

Choose a hash map to store each user's login count and a queue (or doubly linked list) to maintain the order of users who have logged in exactly once. The queue allows O(1) retrieval of the earliest single-visit user.

3. Implement Methods

For recordLogin(username): increment the user's count in the hash map. If the count becomes 1, add the username to the queue. If it becomes 2, remove the username from the queue (if present). For getEarliestSingleVisitUser(): remove and return the front of the queue if it still has count 1, otherwise dequeue and continue until a valid user is found or the queue is empty.

4. Analyze Complexity

Explain that both operations are O(1) amortized time: recordLogin does constant work, and getEarliestSingleVisitUser may dequeue multiple stale entries but each user is dequeued at most once. Space complexity is O(n) for n unique users.

5. Discuss Edge Cases and Extensions

Cover scenarios like no single-visit users, users with multiple logins, and concurrent access. Mention potential extensions such as handling timestamps or distributed systems.

Key Points to Mention

  • Use of hash map for O(1) login count updates
  • Use of queue or linked list to maintain order of single-visit users
  • Lazy removal of users who log in again to keep operations efficient
  • Amortized O(1) time complexity for both methods
  • Handling of edge cases such as empty queue or users with multiple logins
  • Considerations for thread safety and scalability in a production environment

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.