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Visa·Software Engineer·Technical Phone Screen·Intermediate

IntermediatePrefer not to say
Apr 2026

Summary

Visa coding interview, one question about string manipulation. Pretty standard stuff, nothing fancy about the setup.

Questions Asked (1)

Q1

Write a program to find all non-repeating characters in a string.

Algorithms & Data Structures
Author's notes

Classic frequency count problem.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the problem: define 'non-repeating characters' (characters that appear exactly once) and discuss constraints like case sensitivity, character set (ASCII vs Unicode), and expected output format. Then propose an efficient solution using a hash map or array to count frequencies in one pass, followed by a second pass to collect characters with count 1, analyzing time and space complexity.

Pro tip: Mention that for ASCII strings, a fixed-size array of 256 integers is more efficient than a hash map, and always discuss trade-offs between time and space. Also, consider edge cases like empty string, all repeating characters, and Unicode to show thoroughness.

1. Clarify requirements

Ask if 'non-repeating' means appearing exactly once, and confirm case sensitivity, character set (ASCII/Unicode), and output format (e.g., list of characters or their indices).

2. Choose data structure

Select a hash map (dictionary) for general character sets or a fixed-size array for ASCII to count frequencies efficiently.

3. Count frequencies

Iterate through the string once, incrementing the count for each character in the chosen data structure.

4. Collect non-repeating characters

Iterate through the string again (or through the data structure) to gather characters with a count of exactly 1, preserving order if needed.

5. Analyze complexity and edge cases

State time complexity O(n) and space complexity O(k) where k is the number of unique characters, and discuss handling of empty strings, all repeating characters, and Unicode.

Key Points to Mention

  • Definition of non-repeating characters (appearing exactly once)
  • Use of hash map or array for frequency counting
  • Time complexity O(n) and space complexity O(k)
  • Two-pass approach: first to count, second to collect
  • Handling edge cases: empty string, all repeating, case sensitivity
  • Alternative approaches (e.g., using collections.Counter in Python) and their trade-offs

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.