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Meta·Software Engineer·Onsite - Coding / Algorithms·Senior

SeniorPrefer not to say
May 2026

Summary

Meta SWE coding round, one problem the whole time but they kept pushing for more optimal solutions. Felt like four interviews in one.

Questions Asked (1)

Q1

Given a list of strings, find the maximum number of strings you can select such that concatenating them produces no repeated characters across the whole result. Walk through progressively more optimized solutions.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Started with backtracking, which felt fine, but they kept asking 'can you do better?' three more times.

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AI HintsAI Generated

Suggested Approach

Start by clarifying constraints and defining a bitmask representation for each string's character set, then walk through brute force, backtracking with pruning, and finally a DP over masks. Emphasize the trade-offs between time and space and how bitmasks enable efficient state representation.

Pro tip: Mention that you can pre-filter strings with duplicate characters and deduplicate identical masks, which drastically reduces the search space in practice. Also, note that the DP over masks is essentially a knapsack-like problem where each string is an item with a 'weight' (character mask) and you maximize count.

1. Clarify and Define

Ask about input size, character set (e.g., lowercase English), and whether order matters. Define the problem as selecting a subset of strings whose concatenated characters are all unique.

2. Brute Force Baseline

Discuss generating all subsets (2^n) and checking each for character uniqueness, noting O(2^n * L) time. This establishes a starting point but is impractical for large n.

3. Bitmask Optimization

Represent each string as a 26-bit integer mask. Pre-filter strings with internal duplicates and deduplicate masks. Then use backtracking with pruning or DP over masks to find the maximum subset size.

4. DP Formulation

Define dp[mask] = max strings achievable with combined character mask 'mask'. Iterate over strings and update dp[new_mask] = max(dp[new_mask], dp[mask] + 1) if masks don't overlap. This is O(n * 2^26) but can be optimized with sparse states.

5. Complexity and Trade-offs

Analyze time and space: DP is O(n * 2^26) worst-case but often much less due to pruning. Compare with backtracking which may be faster for small n. Mention that 2^26 is large but feasible with sparse maps or if character set is smaller.

Key Points to Mention

  • Bitmask representation of character sets for O(1) overlap checks.
  • Preprocessing: remove strings with duplicate characters and deduplicate identical masks.
  • Backtracking with pruning (e.g., sort by length or mask size) as an alternative to DP.
  • DP state definition: dp[mask] = max count, and transition using non-overlapping masks.
  • Complexity analysis: O(n * 2^26) time, O(2^26) space, but practical optimizations reduce it.
  • Trade-offs: DP guarantees optimal but may be memory-heavy; backtracking may be faster for small inputs.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.