← Bytedance Interview Insights
I knew the general shape of the solution pretty fast: walk through the list, dump everything that ends before the new interval starts, then keep merging anything that overlaps by stretching the new interval's bounds, then tack on the rest.
Use a linear scan to process intervals in three phases: add all intervals that end before the new interval starts, merge all overlapping intervals with the new interval, then add the remaining intervals. This achieves O(n) time and O(n) space, which is optimal since the input is already sorted.
Pro tip: Clarify edge cases upfront: empty input, new interval before all, after all, or overlapping multiple intervals. Also mention that if the input weren't sorted, you'd need to sort first (O(n log n)), but since it's sorted, linear is optimal.
Ask if intervals are inclusive/exclusive, if the list can be empty, and if the new interval is guaranteed to be valid. Confirm that the result should be a new list or modified in-place.
Explain that you'll iterate through intervals: first add those ending before the new interval starts, then merge overlapping ones by updating the new interval's bounds, and finally add the rest.
Trace a concrete example (e.g., intervals = [[1,3],[6,9]], new = [2,5]) to demonstrate how the phases work and how merging updates the start and end.
State time O(n) and space O(n) for the output. Discuss edge cases: new interval before all, after all, overlapping multiple, or empty input.
Implement with a single loop and clear conditions. Use a result list and append intervals as you go, avoiding unnecessary nested loops.
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