← Bytedance Interview Insights
The basic idea clicked fast but I kept second-guessing myself on the negative number case.
Use dynamic programming with two variables to track the maximum and minimum product ending at the current position, updating them as you iterate through the array. The minimum product is crucial because multiplying by a negative number can turn it into the maximum. Keep a global maximum to record the best product seen so far.
Pro tip: Explicitly handle zeros by resetting both max and min to 1 (or the current element) because any subarray containing a zero has product zero, which is never optimal unless all numbers are zero. Also, clarify that the subarray must be non-empty, so initialize with the first element.
Restate the problem to ensure understanding: find the maximum product of any non-empty contiguous subarray in O(n) time. Ask about constraints (e.g., array size, integer range) and edge cases (all zeros, single element).
Maintain two variables: max_prod and min_prod, representing the maximum and minimum product of subarrays ending at the current index. Also keep a global max_product to track the overall maximum.
Initialize max_prod, min_prod, and max_product to the first element. Iterate from the second element, and for each number, compute new max_prod and min_prod using the previous values and the current number.
Update max_product with the new max_prod. If the current number is zero, reset max_prod and min_prod to 1 (or handle by setting to the next element) to effectively start a new subarray after the zero.
After the loop, return max_product. Discuss time complexity O(n) and space complexity O(1), and mention that this approach handles negative numbers and zeros correctly.
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