← Bytedance Interview Insights

Bytedance·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jun 2026

Summary

Bytedance SWE coding round, one algorithmic problem on subsets with duplicates. Pretty standard backtracking territory but the dedup logic is the part that actually matters and where I had to think carefully.

Questions Asked (1)

Q1

Given an integer array that may contain duplicates, return all possible unique subsets (the power set) without any duplicate subsets.

Algorithms & Data Structures
Author's notes

I knew the no-duplicates version cold, so my first instinct was to just write that and slap a set on the output.

Create a free account to read the full note

AI HintsAI Generated

Suggested Approach

Sort the array to group duplicates, then use backtracking to generate subsets while skipping duplicate elements at the same recursion level. Alternatively, use an iterative approach that builds subsets and avoids duplicates by only adding new elements if they differ from the previous element. Emphasize the importance of handling duplicates to ensure unique subsets.

Pro tip: Mention that sorting is crucial for efficient duplicate skipping, and clarify that duplicates are skipped only at the same decision level to avoid missing valid subsets. Also, discuss time complexity: O(2^n) subsets, but with duplicates, the actual number is less.

1. Clarify and Sort

Confirm that the output should contain unique subsets and that order doesn't matter. Sort the input array to bring duplicates together.

2. Choose Approach

Decide between backtracking (DFS) or iterative bitmask. Backtracking is more intuitive for handling duplicates.

3. Implement Backtracking with Duplicate Skip

At each recursion level, iterate through elements, skip if the current element equals the previous and the previous was not used in this branch. Add the current subset to the result at each step.

4. Analyze Complexity

Explain that the number of subsets is at most 2^n, and with duplicates, it's less. Time complexity is O(2^n) and space O(n) for recursion stack.

5. Test with Edge Cases

Test with empty array, all duplicates, and mixed duplicates to ensure correctness.

Key Points to Mention

  • Sorting the array to handle duplicates efficiently
  • Backtracking with a 'used' array or index-based skipping
  • Skipping duplicates at the same recursion level to avoid duplicate subsets
  • Time and space complexity analysis
  • Edge cases: empty array, all elements same, negative numbers
  • Comparison with iterative approach and trade-offs

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.