← Bytedance Interview Insights
My first instinct was pure greedy, just launch the drone at every station you pass and call it done.
Model the problem as a shortest path on a line where walking edges connect adjacent positions and drone edges connect each station to position+10 with zero cost. Use dynamic programming or Dijkstra to compute the minimum walking distance to T, considering only relevant positions (stations, station+10, and T).
Pro tip: Clarify that drone launches are only from stations and that the drone moves exactly 10 units forward; if T is not exactly reachable, you may need to walk the remainder. Also, consider if multiple drones can be used sequentially from different stations.
Restate the problem: start at 0, target T, stations at sorted positions, drone moves exactly 10 forward from a station at zero walking cost. Identify that you can walk any distance forward at cost equal to distance.
Define state as current position. Transitions: walk to any forward position (cost = distance) or if at a station, launch drone to position+10 (cost = 0). Only positions that matter are 0, T, stations, and station+10.
Since the graph is a DAG (only forward edges), use DP: dp[i] = min walking distance to reach position i. Process positions in increasing order. Alternatively, use Dijkstra for general graphs.
Initialize dp[0]=0, others infinity. For each position in sorted order, update dp[pos+10] if pos is a station, and update dp[next] for walking. Handle cases where T is before first station, or no stations, or drone overshoots T.
Time O(N log N) due to sorting (if not already sorted) and O(N) DP. Space O(N). Discuss if greedy works: not always, because using a drone might skip a station that could be useful later.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.