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Bytedance·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
May 2026

Summary

Bytedance software engineer interview with at least one coding problem that looked like LeetCode 620 or something close to it. Not a ton of detail to go on but the problem itself is worth knowing.

Questions Asked (1)

Q1

Given a table of movies, write a SQL query to find all movies that have at least one description that is not 'boring', and return them ordered by rating descending. (LeetCode 620 or similar variant)

Algorithms & Data Structures
Author's notes

Pretty standard SQL filter and sort, nothing tricky about the logic itself.

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AI HintsAI Generated

Suggested Approach

First, clarify the table schema and the exact filtering condition: 'at least one description that is not boring' means the movie has at least one row where description != 'boring'. Use a subquery with EXISTS or IN to filter movies, then order by rating descending. Alternatively, use GROUP BY with HAVING COUNT(CASE WHEN description != 'boring' THEN 1 END) > 0.

Pro tip: Mention that if the table has multiple rows per movie (e.g., multiple descriptions), you must deduplicate movies in the output. Also, consider performance: EXISTS is often more efficient than IN for large datasets, and indexing on description and movie_id can help.

1. Understand the schema and requirements

Identify the table name, columns (e.g., movie_id, description, rating), and clarify that a movie can have multiple descriptions. Confirm that 'not boring' means description != 'boring' and that we need movies with at least one such description.

2. Choose a filtering method

Decide between using a subquery with EXISTS/IN or using GROUP BY with HAVING. EXISTS is suitable for correlated subqueries, while GROUP BY aggregates per movie.

3. Write the SQL query

Construct the query: SELECT movie_id (or all columns) FROM table WHERE movie_id IN (SELECT movie_id FROM table WHERE description != 'boring') ORDER BY rating DESC. Or use GROUP BY movie_id HAVING COUNT(CASE WHEN description != 'boring' THEN 1 END) > 0.

4. Handle duplicates and ordering

If selecting all columns, ensure each movie appears once. Use DISTINCT or GROUP BY. Order by rating descending, and consider secondary sort if needed.

5. Test and optimize

Test with edge cases: movies with only 'boring' descriptions, movies with no descriptions, ties in rating. Discuss potential indexes to improve performance.

Key Points to Mention

  • Use of EXISTS or IN subquery to filter movies with at least one non-boring description
  • Alternative approach using GROUP BY with HAVING COUNT(CASE WHEN description != 'boring' THEN 1 END) > 0
  • Handling duplicates when a movie has multiple rows (e.g., using DISTINCT or GROUP BY)
  • Ordering by rating descending, and considering NULL ratings or ties
  • Performance considerations: indexing on description and movie_id, and the efficiency of EXISTS vs IN
  • Edge cases: movies with no descriptions, all descriptions are 'boring', or multiple non-boring descriptions

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.