Started with brute force because I figured they'd want to see my thinking.
Count the frequency of each digit, then greedily build the largest palindrome by placing the largest possible digits at the ends, using the largest remaining digit as the center if any odd count exists. Handle edge cases like all zeros and leading zeros by ensuring the first digit is non-zero unless the result is '0'.
Pro tip: Clarify constraints upfront (e.g., input size, whether all digits must be used) and discuss trade-offs between time and space complexity; this shows you think about real-world scenarios and not just the algorithm.
Ask about input size, whether all digits must be used, and how to handle leading zeros. Confirm that the result should be the largest possible palindromic number.
Use an array of size 10 to count occurrences of each digit. This allows O(n) time and O(1) space for the counting step.
Iterate from digit 9 down to 0, appending half of each digit's count to the left half. This ensures the largest possible digits are placed at the most significant positions.
Combine the left half, a middle digit (the largest digit with an odd count, if any), and the reverse of the left half. Handle the all-zeros case separately.
Check for leading zeros: if the result starts with '0' and length > 1, it's invalid; return '0' if all digits are zero. Also consider if no palindrome can be formed (e.g., empty input).
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.