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Jump Trading·Software Engineer·Onsite - Coding / Algorithms·Senior

SeniorPrefer not to say
Jun 2026

Summary

Jump Trading C++ developer loop, and the vector question ate up most of the session. Four parts, progressively harder, and the interviewer was clearly not satisfied with just knowing that you double the capacity.

Questions Asked (7)

Q1

Sketch the data layout for a simplified Vector<T> and implement size(), capacity(), operator[], and the fast path of push_back. What growth factor do you use when capacity runs out, and why does that make push_back amortized O(1)?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

I went with the three-pointer layout (begin, end, end-of-capacity) which felt natural.

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AI HintsAI Generated

Suggested Approach

Start by sketching the memory layout: a pointer to a dynamically allocated array, a size, and a capacity. Then implement the methods, emphasizing the fast path of push_back (when size < capacity) and the growth strategy (e.g., doubling) that ensures amortized O(1). Explain the amortized analysis using the aggregate method or accounting method.

Pro tip: Mention that the growth factor should be between 1 and 2 (e.g., 1.5 or 2) to balance memory usage and performance, and that using a factor of 2 can lead to memory fragmentation, while 1.5 is often used in practice (e.g., in some standard libraries).

1. Sketch the data layout

Draw a diagram showing a pointer to the heap-allocated buffer, the current size (number of elements), and the capacity (allocated space). Mention that the buffer is contiguous.

2. Implement size(), capacity(), and operator[]

These are trivial: return the size, return the capacity, and return a reference to the element at the given index (with optional bounds checking in debug mode).

3. Implement the fast path of push_back

If size < capacity, construct the new element at buffer[size] and increment size. This is O(1).

4. Explain the growth strategy

When capacity is full, allocate a new buffer of larger capacity (e.g., double or 1.5x), copy/move elements, and deallocate the old buffer. Discuss trade-offs of different growth factors.

5. Analyze amortized O(1)

Use the aggregate method: sum the costs of n push_backs. The total cost is O(n) because each element is copied at most a constant number of times when doubling. Thus, amortized cost per operation is O(1).

Key Points to Mention

  • Contiguous memory layout with pointer, size, and capacity.
  • Fast path of push_back is O(1) when size < capacity.
  • Growth factor: typically 2 or 1.5; explain why not 1 (would be O(n) per push_back).
  • Amortized analysis: total cost of n push_backs is O(n) due to geometric series of copies.
  • Trade-offs: larger growth factor reduces number of reallocations but wastes more memory; smaller factor saves memory but increases reallocations.
  • Exception safety: if reallocation fails, the original vector should remain unchanged (strong exception guarantee) or at least valid (basic guarantee).

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Why is 'new T[n]' the wrong way to allocate a vector's internal buffer? Show how you'd allocate raw storage, construct elements into it explicitly, and tear everything down correctly. Then implement the full rule of five.

Technical Trade-offsSystem Design
Author's notes

This is where I felt most confident.

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AI HintsAI Generated

Suggested Approach

Start by explaining the fundamental problem: `new T[n]` default-constructs n objects, which is incorrect for a vector that needs to manage uninitialized storage and control construction timing. Then demonstrate the correct approach using raw memory allocation (e.g., `operator new` or `std::allocator`), placement new for construction, and explicit destructor calls for cleanup. Finally, implement the rule of five (destructor, copy constructor, copy assignment, move constructor, move assignment) ensuring exception safety and proper resource management.

Pro tip: Emphasize that `new T[n]` requires T to be default-constructible and immediately constructs all elements, which is inefficient and semantically wrong for a vector that should only construct elements when needed. Also, mention that using `std::allocator` or `operator new` separates allocation from construction, enabling strong exception guarantees and support for non-default-constructible types.

1. Explain why `new T[n]` is wrong

Discuss that `new T[n]` default-constructs n objects immediately, which is wasteful and incorrect for a vector that needs to manage uninitialized memory and construct elements only when added. It also requires T to be default-constructible and doesn't allow separate allocation from construction.

2. Show raw storage allocation

Demonstrate allocating raw, uninitialized memory using `operator new` (e.g., `static_cast<T*>(::operator new(n * sizeof(T)))`) or `std::allocator<T>::allocate(n)`. Explain that this only reserves memory without constructing objects.

3. Construct elements explicitly

Use placement new to construct elements into the raw storage: `new (ptr + i) T(args...)`. Show how to handle exceptions during construction by destroying already-constructed elements and deallocating memory.

4. Tear down correctly

Explicitly call destructors for each constructed element (e.g., `ptr[i].~T()`) and then deallocate the raw memory using `operator delete` or `std::allocator<T>::deallocate`. Ensure this happens in the destructor and during exception cleanup.

5. Implement the rule of five

Write the destructor, copy constructor, copy assignment operator, move constructor, and move assignment operator. Ensure deep copying, move semantics (stealing resources), self-assignment safety, and exception safety (e.g., copy-and-swap idiom).

Key Points to Mention

  • Separation of allocation and construction: raw memory allocation vs. object construction.
  • Placement new syntax and its role in constructing objects in pre-allocated memory.
  • Explicit destructor calls and deallocation to avoid resource leaks.
  • Exception safety: handling exceptions during construction and assignment (e.g., strong guarantee).
  • Rule of five: destructor, copy constructor, copy assignment, move constructor, move assignment.
  • Move semantics: efficiently transferring resources and leaving source in a valid state.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q3

If T's copy constructor can throw and it throws partway through relocating elements to a new buffer during push_back, what state is the vector left in? What exception-safety guarantee can you provide, and how do you implement the reallocation path to achieve it?

Technical Trade-offsAlgorithms & Data Structures
Author's notes

Probably the hardest part of the whole interview.

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AI HintsAI Generated

Suggested Approach

Explain that if T's copy constructor throws during reallocation, the vector must remain unchanged to provide the strong exception guarantee. Describe the implementation strategy: allocate new buffer, copy elements one by one, and only commit (swap pointers, update size/capacity) after all copies succeed; if any copy throws, deallocate the new buffer and propagate the exception, leaving the original vector intact.

Pro tip: Mention that this is why std::vector::push_back provides the strong exception guarantee when T's copy constructor doesn't throw, but only the basic guarantee if it can throw. Also note that move semantics (if noexcept) can be used to achieve the strong guarantee even for throwing copy constructors, as in C++11 and later.

1. Identify the exception-safety guarantee

State that the vector should provide the strong exception guarantee: if an exception is thrown, the vector remains unchanged (no effects).

2. Describe the reallocation process

Explain that reallocation involves allocating a new buffer, copying existing elements to it, and then destroying the old elements and deallocating the old buffer.

3. Handle exceptions during copying

If a copy constructor throws partway through, catch the exception (or use RAII), destroy any successfully copied elements in the new buffer, deallocate the new buffer, and rethrow. The original vector remains untouched.

4. Commit the changes only after success

After all elements are successfully copied, swap the new buffer with the old one (or update pointers), update size and capacity, and then destroy old elements and deallocate old buffer.

5. Discuss implications and alternatives

Mention that if T's copy constructor can throw, push_back may not offer the strong guarantee in all implementations (e.g., if it uses move_if_noexcept). Also note that using move semantics (if noexcept) can preserve the strong guarantee.

Key Points to Mention

  • Strong exception guarantee: vector unchanged if exception thrown.
  • Basic guarantee: vector remains valid but unspecified state.
  • Implementation: allocate new buffer, copy elements, commit only after all succeed.
  • Use RAII or try-catch to clean up partially constructed new buffer.
  • Impact of T's copy constructor throwing on push_back's guarantee.
  • Role of noexcept move constructor in achieving strong guarantee (C++11).

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q4

When relocating elements to a new buffer, how do you decide whether to move them or copy them? What standard utility handles this decision, and why does it matter for exception safety?

Technical Trade-offsAlgorithms & Data Structures
Author's notes

std::move_if_noexcept.

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AI HintsAI Generated

Suggested Approach

Explain that the decision hinges on the type's move semantics and exception guarantees, and that std::move_if_noexcept is the standard utility that automates this choice. Emphasize that this matters for strong exception safety: if moving can throw, copying preserves the original buffer, allowing rollback.

Pro tip: Mention that std::move_if_noexcept returns an rvalue reference only if the move constructor is noexcept or if the type is not copyable; otherwise it returns a const lvalue reference, forcing a copy. This shows you understand the precise conditions and the trade-off between performance and safety.

1. Identify the decision criteria

Determine whether the type has a noexcept move constructor and whether it is copyable. If moving can throw and copying is available, prefer copying to maintain exception safety.

2. Introduce std::move_if_noexcept

State that std::move_if_noexcept is the standard utility that conditionally casts to an rvalue reference based on the type's move constructor's noexcept specification and copyability.

3. Explain the exception safety guarantee

Describe how using move_if_noexcept enables the strong exception guarantee: if an exception occurs during relocation, the original buffer remains unchanged because elements were copied, not moved.

4. Discuss performance implications

Note that when moves are noexcept, move_if_noexcept allows efficient moves; otherwise, it falls back to copying, which may be slower but ensures safety.

5. Connect to real-world usage

Mention that standard containers like std::vector use this technique when reallocating, balancing performance and exception safety.

Key Points to Mention

  • std::move_if_noexcept is defined in <utility> and returns T&& if T's move constructor is noexcept or T is not copyable, else const T&.
  • The strong exception guarantee requires that if an exception is thrown during relocation, the original buffer remains valid and unchanged.
  • Moving from an element can leave it in a valid but unspecified state, so if a later move throws, the original buffer may be corrupted.
  • Copying preserves the source, allowing rollback, but may be less efficient than moving.
  • The noexcept specification on move constructors is crucial; types with throwing move constructors are copied instead.
  • Standard containers like std::vector use move_if_noexcept during reallocation to provide strong exception safety when possible.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q5

Which type traits let you optimize your vector implementation: specifically, which trait lets you use memcpy instead of element-by-element construction, which lets you skip destructor calls, and which governs the move-vs-copy decision during reallocation?

Technical Trade-offsAlgorithms & Data Structures
Author's notes

std::is_trivially_copyable for the memcpy path, std::is_trivially_destructible to skip destructor loops, and std::is_nothrow_move_constructible for the move-vs-copy decision.

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AI HintsAI Generated

Suggested Approach

Name the three type traits directly: std::is_trivially_copyable for memcpy, std::is_trivially_destructible for skipping destructors, and std::is_nothrow_move_constructible (or std::move_if_noexcept) for move-vs-copy during reallocation. Then explain how each trait enables a specific optimization and why it's safe, showing you understand the underlying object model.

Pro tip: Mention that these traits are the foundation of std::vector's implementation in major standard libraries, and that using them correctly is essential for exception safety and performance.

1. Identify the three traits

State the traits: std::is_trivially_copyable, std::is_trivially_destructible, and std::is_nothrow_move_constructible (or std::move_if_noexcept).

2. Explain memcpy optimization

Describe how std::is_trivially_copyable allows using memcpy for copying elements, avoiding per-element copy constructors.

3. Explain destructor skipping

Describe how std::is_trivially_destructible allows skipping destructor calls when destroying elements, improving performance.

4. Explain move-vs-copy decision

Describe how std::is_nothrow_move_constructible (or std::move_if_noexcept) determines whether to move or copy elements during reallocation to maintain strong exception safety.

5. Connect to real-world usage

Mention that these optimizations are used in standard library implementations of std::vector and are key to high-performance code.

Key Points to Mention

  • std::is_trivially_copyable enables memcpy for copying
  • std::is_trivially_destructible allows skipping destructor calls
  • std::is_nothrow_move_constructible (or std::move_if_noexcept) governs move-vs-copy during reallocation
  • These traits are used in std::vector implementations for performance
  • Exception safety: move only if noexcept, otherwise copy to maintain strong guarantee
  • Trivial types can be bitwise copied and don't need destruction

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q6

How would you extend this vector to support insert and erase in the middle, and what invalidation rules for iterators and references follow from your reallocation strategy?

System DesignTechnical Trade-offs
Author's notes

Didn't get deep into this one, it was more of a closing discussion.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the current vector implementation (e.g., contiguous dynamic array) and then propose extending it with insert and erase operations that shift elements to maintain contiguity. Discuss how reallocation may occur when capacity is exceeded, and derive iterator/reference invalidation rules based on whether reallocation happens and which elements are moved.

Pro tip: Emphasize that insert/erase in the middle are O(n) due to shifting, and that reallocation invalidates all iterators/references, while shifting invalidates only those at or after the modification point. This shows you understand performance and safety trade-offs.

1. Clarify current vector design

Confirm that the vector is a contiguous dynamic array with size, capacity, and a pointer to heap-allocated memory. Mention that it supports random access and amortized O(1) push_back.

2. Implement insert

To insert at position pos, if size == capacity, reallocate to a larger buffer (e.g., double capacity) and copy/move elements. Then shift elements from pos to end one slot to the right, place the new element, and increment size.

3. Implement erase

To erase at position pos, shift elements from pos+1 to end one slot to the left, destroy the last element, and decrement size. No reallocation occurs, but elements after pos are moved.

4. Analyze reallocation strategy

Explain that reallocation happens only when inserting and size == capacity. The new capacity is typically 2x (or 1.5x) to maintain amortized O(1) for push_back, but insert in the middle is O(n) due to shifting.

5. Derive invalidation rules

If reallocation occurs, all iterators and references are invalidated. Otherwise, for insert, iterators/references at or after pos are invalidated (due to shifting); for erase, iterators/references at or after pos are invalidated. Elements before pos remain valid.

Key Points to Mention

  • Contiguous memory layout and the need to shift elements for insert/erase.
  • Reallocation strategy: when size == capacity, allocate new memory, move elements, and deallocate old memory.
  • Amortized O(1) for push_back but O(n) for insert/erase in the middle due to shifting.
  • Iterator and reference invalidation: reallocation invalidates all; shifting invalidates those at or after the modification point.
  • Exception safety: use move semantics if possible, and ensure strong exception guarantee for insert/erase.
  • Alternative designs: deque or list for frequent middle insertions/deletions, but with different trade-offs.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q7

How would you add an Allocator template parameter to this vector using std::allocator_traits? What specifically changes in the move-assignment operator?

System DesignTechnical Trade-offs
Author's notes

I gave a surface-level answer about wrapping all allocations through allocator_traits::allocate and construct.

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AI HintsAI Generated

Suggested Approach

Start by explaining the general pattern of templating a container on an allocator and using std::allocator_traits to abstract allocator operations. Then focus on the move-assignment operator, highlighting how allocator propagation traits (propagate_on_container_move_assignment) determine whether you can steal the buffer or must move element-by-element. Conclude with the implications for exception safety and performance.

Pro tip: Mention that if propagate_on_container_move_assignment is false and allocators are unequal, you cannot steal the buffer—you must move elements individually, which is a common pitfall in high-performance code. Also note that std::allocator_traits provides a uniform interface even for allocators that don't define all members.

1. Template the class on Allocator

Add a template parameter `class Allocator = std::allocator<T>` to the vector class and store an allocator instance. Use `std::allocator_traits<Allocator>` for all allocation, deallocation, construction, and destruction operations.

2. Use allocator_traits for memory management

Replace direct calls to `allocator.allocate`, `allocator.deallocate`, etc., with `std::allocator_traits<Allocator>::allocate`, `deallocate`, `construct`, and `destroy`. This ensures compatibility with minimal allocators.

3. Implement move-assignment with propagation traits

In the move-assignment operator, check `std::allocator_traits<Allocator>::propagate_on_container_move_assignment::value`. If true, move-assign the allocator and steal the buffer. If false, compare allocators: if equal, steal the buffer; if unequal, move elements individually.

4. Handle exception safety and self-assignment

Ensure strong exception safety by deallocating the old buffer only after successful allocation or by using copy-and-swap. Also guard against self-move-assignment.

5. Discuss trade-offs and performance

Explain that propagation traits affect performance: stealing the buffer is O(1), while element-wise move is O(n). Mention that unequal allocators force the slower path, which is crucial in latency-sensitive systems like trading.

Key Points to Mention

  • std::allocator_traits provides a uniform interface and defaults for allocator operations.
  • Allocator propagation traits: propagate_on_container_move_assignment, propagate_on_container_copy_assignment, propagate_on_container_swap.
  • Move-assignment logic depends on whether the allocator propagates and whether the two allocators compare equal.
  • If propagation is false and allocators are unequal, you must move elements individually, which can throw and is slower.
  • Use std::allocator_traits<Allocator>::construct and destroy instead of calling allocator methods directly.
  • Consider the impact on exception safety and the strong guarantee when implementing move-assignment.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.